[英]bomb including ordered pairs in python
I'm trying to do this task in python 3: Get as many Ordered Pairs as the User Wants, Seprated with space, like: (1,3) (5,6)... Print a 10 × 10 Square Made with Xs.我正在尝试在 python 3 中执行此任务:获取尽可能多的用户想要的有序对,用空格分隔,例如:(1,3) (5,6)... 打印一个 10 × 10 Square Made with Xs . except for the Ordered Pairs given, print Os on their place.除了给出的有序对,在它们的位置打印 Os。 Note: the Origin (0,0) of the Imaginary Coordinate System on this Square is the Left-Top place注意:这个正方形上虚坐标系的原点(0,0)是左上角
well I wrote this code:好吧,我写了这段代码:
x = input()
L=(x.split())
for i in range(0,len(L)):
for n in range (0,10):
for m in range (0,10):
if (m == int((L[i])[1]) and n == int((L[i])[3])):
print("O", end=" ")
else:
print("X", end=" ")
print()
but it has a Problem: it prints more than one Square.但它有一个问题:它打印了多个 Square。 when I give two inputs, it Prints two Squares:( like this:当我给出两个输入时,它会打印两个正方形:( 像这样:
(0,0) (3,5)
O X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X O X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
but it's Supposed to be like:但它应该是这样的:
(0,0) (1,2) (3,3) (1,5) (8,9)
O X X X X X X X X X
X X X X X X X X X X
X O X X X X X X X X
X X X O X X X X X X
X X X X X X X X X X
X O X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X O X
any help would be Appreciated.任何帮助,将不胜感激。 I'm a Beginner:(我是初学者:(
Try this:尝试这个:
x = "(0,0) (1,2) (3,3) (1,5) (8,9)"
x = [eval(i.replace("(", "").replace(")", "")) for i in x.split()]
X = np.array(x)
cols = X[:, 0].max()
rows = X[:, 1].max()
d = pd.DataFrame(np.zeros((max(rows, cols)+1, max(rows, cols)+1))).replace(0, "X")
d: d:
0 1 2 3 4 5 6 7 8 9
0 X X X X X X X X X X
1 X X X X X X X X X X
2 X X X X X X X X X X
3 X X X X X X X X X X
4 X X X X X X X X X X
5 X X X X X X X X X X
6 X X X X X X X X X X
7 X X X X X X X X X X
8 X X X X X X X X X X
9 X X X X X X X X X X
R = [i[1] for i in x]
C = [i[0] for i in x]
for i in range(len(R)):
print("Row:", R[i], end="\t")
print("Col:", C[i])
for i in range(len(R)):
d.iloc[R[i], C[i]] = "0"
Row: 0 Col: 0
Row: 2 Col: 1
Row: 3 Col: 3
Row: 5 Col: 1
Row: 9 Col: 8
d: d:
0 1 2 3 4 5 6 7 8 9
0 0 X X X X X X X X X
1 X X X X X X X X X X
2 X 0 X X X X X X X X
3 X X X 0 X X X X X X
4 X X X X X X X X X X
5 X 0 X X X X X X X X
6 X X X X X X X X X X
7 X X X X X X X X X X
8 X X X X X X X X X X
9 X X X X X X X X 0 X
import ast
user_input = input()
ordered_pairs = [ast.literal_eval(i) for i in user_input.split(' ')]
l = [['X' for j in range(10)] for i in range(10)]
for x, y in ordered_pairs: l[y][x] = 'O'
print('\n', user_input, sep='')
for i in l:
print(*i)
(0,0) (1,2) (3,3) (1,5) (8,9)
O X X X X X X X X X
X X X X X X X X X X
X O X X X X X X X X
X X X O X X X X X X
X X X X X X X X X X
X O X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X X X
X X X X X X X X O X
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