将 `const` 数组的元素设置为 c++ 中另一个数组的长度

Question

I defined a const int array like this:

const int arr[] = { 100 , 200, 300, 400 };

Now i want to set one of the elements of above array as the length of another array like the following:

char buffer[arr[3]];

But it gave me a compile time error :

 non-constant arguments or reference to a non-constant symbol

I studied this This question to solve my problem but i became confuse about these questions:

• Why can't i set an element of a const array as the length of another array?
• Are the elements of a const array constant or read only?
• What is the differences between a const and read only statements in c?

Regards!

Answer 1

There are really two different kinds of constant "things" in C++.

The one that you know as the const keyword: you can't modify it at runtime .

And the one that's known as a constant value to the compiler at compile time .

That one would be:

constexpr int arr[] = { 100 , 200, 300, 400 };

C++ requires an array size to be a constexpr expression, and not just a const one. Some compilers let you get away with just a const size (and not even that, actually), but that's not the current C++ standard.

You might be wondering why, in this case, this is not a constant value at compile time. After all: it's right there. It's three digits. An integer. It can't go anywhere.

Well, that would be a different, pedantic question, but is mostly irrelevant. Your compiler is well within its rights to reject a non- constexpr expression in this case, as ill-formed. So it does. And you have no choice but to obey your compiler's demands.

Answer 2

I realized const and constexpr in the following statements:

• const : To be evaluated at runtime and it's accepted by compiler and can't change in runtime.

   const int a = std::cin.get(); // correct const int b = 5; // correct

• constexpr : To be evaluate at compile time

  constexpr int b = std::cin.get(); // incorrect (because it evaluate in compile time, so compiler cannot forecast the value at compile time) constexpr int b = 65; // correct

Now in my code as i understood, i think the char buffer is evaluate the array size at compile time and const int arr will be avaluate at runtime . so cannot set char buffer array length with a number that will be evaluate at runtime and we need a constant value.

Notice:

const int arr[] = { 100 , 200, 300, 400 };     // Evaluate at runtime
char buffer[arr[3]];                           // Evaluate at compile time and cause error

So we need a const number that evaluated at compile time to set array length of the char buffer :

constexpr int arr[] = { 100 , 200, 300, 400 };     // Evaluate at compile time
char buffer[arr[3]];                               // Evaluate at compile time