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C ++指向const指针的const数组的指针

[英]C++ Pointer to const array of const pointers

I've created a const array of const pointers like so: 我已经创建了const指针的const数组,如下所示:

const char* const sessionList[] = {
    dataTable0,
    dataTable1,
    dataTable2,
    dataTable3
};

What is the correct syntax for a regular non-const pointer to this array? 这个数组的常规非const指针的正确语法是什么? I thought it would be const char** , but the compiler thinks otherwise. 我认为它将是const char** ,但编译器认为不然。

如果您确实需要一个指向数组的指针,正如标题所示,那么这就是语法:

const char* const (*ptr)[4] = &sessionList;
const char* const sessionList[] = { ... };

is better written as: 写得更好:

char const* const sessionList[] = { ... };

Type of sessionList[0] is char const* const . sessionList[0]类型是char const* const
Hence, type of &sessionList[0] is char const* const* . 因此, &sessionList[0]char const* const*

You can use: 您可以使用:

char const* const* ptr = &sessionList[0]; 

or 要么

char const* const* ptr = sessionList; 

That declares a pointer to the elements of sessionList . 这声明了一个指向sessionList元素的sessionList If you want to declare a pointer to the entire array, it needs to be: 如果要声明指向整个数组的指针,则需要:

char const* const (*ptr)[4] = &sessionList; 

与为数组元素声明的类型相同,添加了额外的*

const char* const *

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