I've created a const array of const pointers like so:
const char* const sessionList[] = {
dataTable0,
dataTable1,
dataTable2,
dataTable3
};
What is the correct syntax for a regular non-const pointer to this array? I thought it would be const char**
, but the compiler thinks otherwise.
如果您确实需要一个指向数组的指针,正如标题所示,那么这就是语法:
const char* const (*ptr)[4] = &sessionList;
const char* const sessionList[] = { ... };
is better written as:
char const* const sessionList[] = { ... };
Type of sessionList[0]
is char const* const
.
Hence, type of &sessionList[0]
is char const* const*
.
You can use:
char const* const* ptr = &sessionList[0];
or
char const* const* ptr = sessionList;
That declares a pointer to the elements of sessionList
. If you want to declare a pointer to the entire array, it needs to be:
char const* const (*ptr)[4] = &sessionList;
与为数组元素声明的类型相同,添加了额外的*
:
const char* const *
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