[英]How to change button state upon press tkinter
I am programming a calculator that does many things and I wanted to ask how to change a buttons state upon its press.我正在编写一个可以做很多事情的计算器,我想问一下如何在按下按钮时更改按钮 state。 I am working with the following code:我正在使用以下代码:
import math, sqlite3
from tkinter import *
root = Tk()
x_are = Label(root)
x_are.grid(row=0, column=0)
x_are_ = Label(root)
x_are_.grid(row=0, column=0)
boo = True
bool_ = True
formula_entry = ''
def geometric_calc_press():
global bool_
def formula():
global bool_, state, formula_entry
if bool_:
formula_entry = Entry(geometric_calc, width=66)
formula_entry.grid(row=1, column=0, columnspan=1000)
bool_ = False
def show_searched_formula():
global formula_entry
x = formula_entry.get()
print(x)
def close():
global bool_, state, formula_entry, close, search_
bool_ = True
formula_entry.destroy()
close_.destroy()
search.destroy()
if not bool_:
close_ = Button(geometric_calc, text='Close', command=close, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
highlightthickness=2, relief=SOLID, default='active', padx=80, pady=20)
close_.grid(row=3, column=0)
search = Button(geometric_calc, text='Search', command=show_searched_formula, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
highlightthickness=2, relief=SOLID, default='active', padx=77, pady=20)
search.grid(row=2, column=0)
global root
root.destroy()
geometric_calc = Tk()
bindings = {
'<FocusIn>': {'default': 'active'},
'<FocusOut>': {'default': 'active'}
}
for k, v in bindings.items():
geometric_calc.bind_class('Button', k, lambda e, kwarg=v: e.widget.config(**kwarg))
geometric_calc.geometry('400x415')
geometric_calc.config(bg='black')
formula_finder = Button(geometric_calc, text='Formulas', bg='black', fg='lime', highlightcolor="lime",
highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70,
command=formula)
formula_finder.grid(row=0, column=0)
formula_user = Button(geometric_calc, text='Calculate', bg='black', fg='lime', highlightcolor="lime",
highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70)
formula_user.grid(row=0, column=2)
The only relevant part really is the geometric_calc_press function.唯一相关的部分是geometric_calc_press function。 i wanted to be able to fix a bug where the close button deosnt work if the formula button is pressed multiple times (the close button then needs to be pressed the same amount of times.)so I wanted to disable the formula button when pressed until the close button is pressed.我希望能够修复一个错误,如果多次按下公式按钮(关闭按钮然后需要按下相同的次数),关闭按钮不起作用。所以我想在按下时禁用公式按钮直到关闭按钮被按下。 I don't really know how to do that though so i am asking here.我真的不知道该怎么做,所以我在这里问。
You can deactivate button with您可以使用停用按钮
button.config(state="disabled")
and activate it back with并用
button.config(state="normal")
or或者
button.config(state="active")
BTW: the same way you can also deactivate other widgets - ie.顺便说一句:您也可以以同样的方式停用其他小部件 - 即。 Label
, Entry
, etc. Other widgets may have different states - ie. Label
, Entry
等。其他小部件可能有不同的状态 - 即。 Entry
has state "read-only"
(but it doesn't have "active"
) Entry
有 state "read-only"
(但它没有"active"
)
Minimal working example最小的工作示例
import tkinter as tk # PEP8: `import *` is not preferred
# --- functions ---
def on_press_1():
b1.config(state="disabled")
l1.config(state="disabled")
e1.config(state="disabled") # or `readonly`
def on_press_2():
b1.config(state="normal") # or `active`
l1.config(state="normal") # or `active`
e1.config(state="normal")
# --- main ---
root = tk.Tk()
l1 = tk.Label(root, text="Label Text")
l1.pack()
e1 = tk.Entry(root)
e1.insert(0, "Entry Text")
e1.pack()
b1 = tk.Button(root, text="Deactivate", command=on_press_1)
b1.pack()
b2 = tk.Button(root, text="Activate", command=on_press_2)
b2.pack()
root.mainloop()
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