[英]How to change button state upon press tkinter
我正在編寫一個可以做很多事情的計算器,我想問一下如何在按下按鈕時更改按鈕 state。 我正在使用以下代碼:
import math, sqlite3
from tkinter import *
root = Tk()
x_are = Label(root)
x_are.grid(row=0, column=0)
x_are_ = Label(root)
x_are_.grid(row=0, column=0)
boo = True
bool_ = True
formula_entry = ''
def geometric_calc_press():
global bool_
def formula():
global bool_, state, formula_entry
if bool_:
formula_entry = Entry(geometric_calc, width=66)
formula_entry.grid(row=1, column=0, columnspan=1000)
bool_ = False
def show_searched_formula():
global formula_entry
x = formula_entry.get()
print(x)
def close():
global bool_, state, formula_entry, close, search_
bool_ = True
formula_entry.destroy()
close_.destroy()
search.destroy()
if not bool_:
close_ = Button(geometric_calc, text='Close', command=close, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
highlightthickness=2, relief=SOLID, default='active', padx=80, pady=20)
close_.grid(row=3, column=0)
search = Button(geometric_calc, text='Search', command=show_searched_formula, bg='black', fg='lime', highlightcolor="lime", highlightbackground="lime",
highlightthickness=2, relief=SOLID, default='active', padx=77, pady=20)
search.grid(row=2, column=0)
global root
root.destroy()
geometric_calc = Tk()
bindings = {
'<FocusIn>': {'default': 'active'},
'<FocusOut>': {'default': 'active'}
}
for k, v in bindings.items():
geometric_calc.bind_class('Button', k, lambda e, kwarg=v: e.widget.config(**kwarg))
geometric_calc.geometry('400x415')
geometric_calc.config(bg='black')
formula_finder = Button(geometric_calc, text='Formulas', bg='black', fg='lime', highlightcolor="lime",
highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70,
command=formula)
formula_finder.grid(row=0, column=0)
formula_user = Button(geometric_calc, text='Calculate', bg='black', fg='lime', highlightcolor="lime",
highlightbackground="lime", highlightthickness=2, relief=SOLID, default='active', padx=70)
formula_user.grid(row=0, column=2)
唯一相關的部分是geometric_calc_press function。 我希望能夠修復一個錯誤,如果多次按下公式按鈕(關閉按鈕然后需要按下相同的次數),關閉按鈕不起作用。所以我想在按下時禁用公式按鈕直到關閉按鈕被按下。 我真的不知道該怎么做,所以我在這里問。
您可以使用停用按鈕
button.config(state="disabled")
並用
button.config(state="normal")
或者
button.config(state="active")
順便說一句:您也可以以同樣的方式停用其他小部件 - 即。 Label
, Entry
等。其他小部件可能有不同的狀態 - 即。 Entry
有 state "read-only"
(但它沒有"active"
)
最小的工作示例
import tkinter as tk # PEP8: `import *` is not preferred
# --- functions ---
def on_press_1():
b1.config(state="disabled")
l1.config(state="disabled")
e1.config(state="disabled") # or `readonly`
def on_press_2():
b1.config(state="normal") # or `active`
l1.config(state="normal") # or `active`
e1.config(state="normal")
# --- main ---
root = tk.Tk()
l1 = tk.Label(root, text="Label Text")
l1.pack()
e1 = tk.Entry(root)
e1.insert(0, "Entry Text")
e1.pack()
b1 = tk.Button(root, text="Deactivate", command=on_press_1)
b1.pack()
b2 = tk.Button(root, text="Activate", command=on_press_2)
b2.pack()
root.mainloop()
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