有没有办法遍历一个列表，并分配一个变量

Question

What I'd like to do is assign variable (a) to each instance of (b). There are 30 folders within (a) It should look like the following: 'm:/groupfolder/susan/01' 'm:/groupfolder/susan/03' 'm:/groupfolder/susan/04'...

Here is what I'm doing -

import os
from os import listdir
a = ('m:/groupfolder/susan')
b = []
for x in os.listdir(a):
   b.append(x)

fha = [b]
for y in fha:
    path = a+b
 Error mesage = "TypeError: can only concatenate str (not "list") to str"

Please let me know what I'm doing wrong - yes I'm relatively new to Python and still learning. Thanks

Answer 1

Instead of collecting all filename in list and then iterating it again. You can simply do it in one step:

import os                                                                                                                                                              

b = []                                                                                                                                                                 
for file in os.listdir(s): 
    print(file) 
    b.append(s+'/'+file) 

print(b) 

Answer 2

Use a list comprehension to get a list of full file paths:

import os
file_paths = [os.path.abspath(f) for f in os.listdir('dir_name')]
print(file_paths)