如何使用 dplyr 过滤 r 中的日期？

Question

Below is my dataset:

df_gather %>% 
  filter(Country.Region %in% c("Italy")) %>%
  arrange(desc(Date)) #%>% 
  # filter(Date %in% c(2020-12-12))

########### output #############

Country.Region Date   Cases_Count
<chr>          <date> <int>

Italy   2020-12-12  1825775     
Italy   2020-12-11  1805873     
Italy   2020-12-10  1787147     
Italy   2020-12-09  1770149     
Italy   2020-12-08  1757394     
Italy   2020-12-07  1742557     
Italy   2020-12-06  1728878     
Italy   2020-12-05  1709991     
Italy   2020-12-04  1688939     
Italy   2020-12-03  1664829     

Issue: when I try to filter this using below code I get 0 rows in return

df_gather %>% 
  filter(Country.Region %in% c("Italy")) %>%
  arrange(desc(Date)) %>%
  filter(Date %in% c(2020-12-12))

######## output #########
0 rows

Also tried with quotes on dates but even then I get same result

df_gather %>% 
  filter(Country.Region %in% c("Italy")) %>%
  arrange(desc(Date)) %>%
  filter(Date %in% c("2020-12-12"))

######## output #########
0 rows

This seems but not able to figure out. Is there a different method of handling dates even in filtering?

Answer 1

The date should be quoted and it is better to compare across similar types ie convert to Date class with as.Date

library(dplyr)
df_gather %>% 
   filter(Country.Region %in% c("Italy")) %>%
   arrange(desc(Date)) %>%
   filter(Date %in% as.Date(c("2020-12-12")))