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如何从 C# WebAPI 返回多个值?

[英]How to return multiple values from a C# WebAPI?

I have a Web API Endpoint with the following signatures.我有一个 Web API 具有以下签名的端点。

 [HttpGet]
 [Route("api/some-endpoint")]
 public IHttpActionResult getAll()
 {
 ...
 ...
    return Ok({ firstList, secondList });
 }

Now, I want to return two list variables firstList, secondList.现在,我想返回两个列表变量firstList、secondList。 How to do that?怎么做?

Return an anonymous type;返回匿名类型; all you're missing is the word new in your code:您所缺少的只是代码中的new这个词:

 [HttpGet]
 [Route("api/some-endpoint")]
 public IHttpActionResult getAll()
 {
 ...
 ...
    return Ok(new { firstList, secondList });
 }

To rename the properties:要重命名属性:

 [HttpGet]
 [Route("api/some-endpoint")]
 public IHttpActionResult getAll()
 {
 ...
 ...
    return Ok(new { propertyName1=firstList, propertyName2=secondList });
 }

Why not a Tuple, as advocated in the other answer?为什么不像其他答案中所提倡的那样使用元组? If you use Tuple your property name are fixed to the name of the Tuple properties (you'll end up with JSON like { "Item1": [... ]...如果您使用 Tuple,您的属性名称将固定为 Tuple 属性的名称(您最终会得到 JSON,例如{ "Item1": [... ]...

you can do this with system.tuple or create a new class or structure like:您可以使用system.tuple执行此操作或创建一个新的 class 或类似以下的结构:

public class TheClass
{
public TheClass(List<string> f,List<string> l)
{
firstList = f;
secendList = l;
}
public List<string> firstList;
public List<string> secendList;
}

and

 [HttpGet]
 [Route("api/some-endpoint")]
 public IHttpActionResult getAll()
 {
 ...
 ...
    return new TheClass(firstList, secondList);
 }

But this class must be on clients to be able to receive and work with it但是这个 class 必须在客户端才能接收和使用它

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