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如何摆脱查询字符串

[英]How to get rid of a query string

SOLVED解决了

I have a kinda stupid issue.我有一个有点愚蠢的问题。 I can't get rid of the query string,.我无法摆脱查询字符串。 Once I put it into the history, I can't find how to remove it.一旦我将它放入历史记录,我就找不到如何删除它。

I have a React app with navigation (Universal Router).我有一个带有导航功能的 React 应用程序(通用路由器)。 I don't believe it is related to the library I use, but rather to a bad use of the URL and History API.我不认为它与我使用的库有关,而是与 URL 和历史记录 API 的错误使用有关。

I have a list of users, and each has a number.我有一个用户列表,每个用户都有一个编号。 I have an input form to enter the number.我有一个输入表格来输入号码。 I append this as a query string in the form /users?nb=1 .我将 append 作为/users?nb=1形式的查询字符串。 This url is submitted to a resolver that searches in an array of paths.这个 url 被提交给一个在路径数组中搜索的解析器。 The action code corresponding to the /users path has a function that reads if a query string is present./users路径对应的操作代码有一个 function,它读取是否存在查询字符串。 If yes, extract the number and push the new path /users/1 .如果是,提取号码并推送新路径/users/1 This almost works: I push in fact /users/1?nb=1 ..这几乎可行:我实际上推/users/1?nb=1 ..

Note: I can of course directly push /users/1 without a query string but this is an exercise.注意:我当然可以直接推送/users/1而无需查询字符串,但这是一个练习。

What is the trick??有什么诀窍?? [EDIT]: override the key search:"" [编辑]:覆盖键search:""

EDIT: https://codesandbox.io/s/universal-router-mobx-demo-jg3um?file=/src/NavBar.js编辑: https://codesandbox.io/s/universal-router-mobx-demo-jg3um?file=/src/NavBar.js

1- the emitting function, creates the query string 1- 发出 function,创建查询字符串

function handleSubmit(e) {
    e.preventDefault();
    let query = Object.fromEntries(new FormData(e.currentTarget));
    const {pathname, search} = window.location 
    const qstring = new URLSearchParams(search);
    for (const k in query){ qstring.append(k, query[k])};
    history.push({ pathname, search: "?" + qstring });
  }

1b - vs a "normal" link 1b - 与“正常”链接相比

const handleClick = (e) => {
    e.preventDefault();
    history.push({ pathname: e.target.pathname });
  };

2- the conditional path (for the query string) 2- 条件路径(用于查询字符串)

const searchString = new URLSearchParams(window.location.search);
const id = searchString.get("nb");
if (id) { return { redirect: `/users/${id}` } }

3- the resolving 3-解决

const page = await router.resolve({ pathname: location.pathname });
if (page.redirect) {
    return history.push({ pathname: page.redirect, search: "" });
 }                                                  ^^^!
return render(<React.StrictMode>{page}</React.StrictMode>, root);

The pb is solved by adding search:"" which removes the trailing query string. pb 通过添加search:""来解决,它删除了尾随的查询字符串。

So as @Ouroborus showed, you just need to add search:'' in the returned url from the resolver to override the previous query string:因此,正如@Ouroborus 所示,您只需要在解析器返回的 url 中添加search:''即可覆盖之前的查询字符串:

history.push({pathname: page.redirect, search:""})

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