在 ||Python 中根据文本文件中的文本打印特定行

Question

I have a text file that contains lots of text however, I only want specific lines/characters printed out. How can do I this?

Example Text-file

  edit 29
    set status enable
    set sender-pattern-type default
    set sender-pattern *
    set recipient-pattern-type default
    set recipient-pattern *
    set sender-ip-type ip-group
    set sender-ip-group 
    set reverse-dns-pattern *
    set reverse-dns-pattern-regexp no
    set authenticated any
    unset tls-profile
    set action relay
    set comment 

I want to print only lines that contain edit , set action and set comment .

How I want it

edit 29
set action relay xyz
set comment xyz
edit 30
set action relay abc
set comment acb
etc.

Current code:

# Save results of command in "Output" while splitting one whole output line into multiple lines (original output).
output = "".join(ssh_stdout.readlines())

# Save SSH output to a text-file.
file = open('outputFortimail.txt', "w")
file.write(output)
file.close()

file.write("\n".join(
    line for line in file.split("\n") if any(line.startswith(x)
                                               for x in
                                               ["edit:", "set sender-ip-mask:", "set comment:", "unset comment"])))
file.close()

Answer 1

Split on newline, filter, and join back on newline:

"\n".join(
    line for line in contents.split("\n") if any(line.startswith(x) for x in ["Name:", "Type:", "Area:"])
)

Where your file is in the string contents .