如何在下拉列表中显示具有完整值的列表并在 flutter 中显示其选择代码？

Question

I have a dropdown field in a form, the list has items like, 1 - Form 4 2 - Form 5 3 - Form 6 4 - Form 7

Now, I want that when the user opens the dropdown, whole 2 - Form 5 should be displayed but when he selects 1, the selected value in the dropdown should display only 1 ie. splitted from hypehn. Can I use valuetransformer or some other way?

              FormBuilderDropdown(
                attribute: "selectFormValue",
                items: <String>['1 - Form 4', '2 - Form 5', '3 - Form 6', '4 - Form 7']
            .map<DropdownMenuItem<String>>((String value) {
          return DropdownMenuItem<String>(
            value: value,
            child: Text(value),
          );
        }).toList(),

              ),

Answer 1

I have a dropdown field in a form, the list has items like, 1 - Form 4 2 - Form 5 3 - Form 6 4 - Form 7

Now, I want that when the user opens the dropdown, whole 2 - Form 5 should be displayed but when he selects 1, the selected value in the dropdown should display only 1 ie. splitted from hypehn. Can I use valuetransformer or some other way?

              FormBuilderDropdown(
                attribute: "selectFormValue",
                items: <String>['1 - Form 4', '2 - Form 5', '3 - Form 6', '4 - Form 7']
            .map<DropdownMenuItem<String>>((String value) {
          return DropdownMenuItem<String>(
            value: value,
            child: Text(value),
          );
        }).toList(),

              ),