尝试生成某些报告时出现名称错误

Question

def state_from_record(state_name):
    state_split = state_name.split(",")
    return state_split

def cases_from_record(covid_cases):
    covid_split = covid_cases.split(",")
    return covid_split

def deaths_from_record(covid_deaths):
    death_split = covid_deaths.split(",")
    return death_split

result1 = state_from_record(result[0])
print(result1) 

This is the second part of the code which continues on:

   import random
    def state_report(state, data_list):
        if state_split is random:
            states = choice(state_split)
            for s in states:
                if states == state_split:
                    return states + "\n" + "Total Confirmed Cases: " + covid_split + "Total Deaths: " + death_split
                else:
                    return "No record found for " + states
    
    result2 = state_report(states, state_split)
    print(result2)

I am trying to use a previous code and it keeps on coming as a name error saying that "states" doesn't exist.

here is my output:

NameError                                 Traceback (most recent call last)
<ipython-input-20-8fee8f642c90> in <module>()
     10                 return "No record found for " + states
     11 
---> 12 result2 = state_report(states, state_split)
     13 print(result2)

NameError: name 'states' is not defined

Answer 1

What you are bumping into is a programming concept called the scope

Imagine these two functions:

def first_func():

    foo = "abc"
    print(foo)

def second_func():

    print(foo)

second_func()

Running this code will raise NameError , because variable foo is out of the scope of the second_func , since it is defined within the boundaries of the first_func .

If you move the variable foo out of the first function, like so:

foo = "abc"

def first_func():

    print(foo)

def second_func():

    print(foo)

second_func()

Both functions will run fine. Because variable foo is now defined in a broader scope and accessible from within both functions.