Python 如果文件夹不存在则创建一个列表

Question

I'm trying to create a list of folders if they don't exist.

I want to iterate through a list of directories and create them, but check each time if the directory exists.

This is my code:

# Create output subdirectories
folders = ['csv','excel','html', 'json']
for folder in folders:
    if not os.path.exists(output_files_path,folder):
        os.mkdir(os.path.join(output_files_path,folder))

This is the error I'm getting:

Traceback (most recent call last):
  File ".\aws_ec2_list_instances.py", line 767, in <module>
    main()
  File ".\aws_ec2_list_instances.py", line 708, in main
    mongo_export_to_file(interactive, aws_account, aws_account_number)
  File "C:\Users\tdun0002\OneDrive - Synchronoss Technologies\Desktop\important_folders\Jokefire\git\jf_cloud_scripts\aws_scripts\python\aws_tools\ec2_mongo.py", line 279, in mongo_export_to_file
    create_directories()
  File "C:\Users\tdun0002\OneDrive - Synchronoss Technologies\Desktop\important_folders\Jokefire\git\jf_cloud_scripts\aws_scripts\python\aws_tools\ec2_mongo.py", line 122, in create_directories
    if not os.path.exists(output_files_path,folder):
TypeError: exists() takes 1 positional argument but 2 were given

How can I do this correctly?

Answer 1

You can use os.makedirs

There is a keyword option exist_ok , if you set to true, will not overwrite it if the folder already exists.

makedirs can also create multiple subdirectories recursively in a single call. This seems to make your job a lot easier in my opinion.

If you're looking for how to call os.path.exists properly:

It seems like you're missing a join call:

os.path.exists(os.path.join(output_files_path,folder))

Answer 2

Just need to pass in the full path to os.path.exists instead of the path as two parameters.

for folder in folders:
    full_path = os.path.join(output_files_path,folder)
    if not os.path.exists(full_path):
        os.mkdir(full_path)