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如何在 tensorflow 中表达此自定义损失 function?

[英]How can I express this custom loss function in tensorflow?

I've got a loss function that fulfills my needs, but is only in PyTorch.我有一个满足我需求的损失 function,但仅在 PyTorch 中。 I need to implement it into my TensorFlow code, but while most of it can trivially be "translated" I am stuck with a particular line:我需要将它实现到我的 TensorFlow 代码中,但是虽然其中大部分都可以简单地“翻译”,但我仍然坚持使用特定的行:

y_hat[:, torch.arange(N), torch.arange(N)] = torch.finfo(y_hat.dtype).max  # to be "1" after sigmoid

You can see the whole code in following and it is indeed pretty straight forward except for that line:您可以在下面看到整个代码,除了该行之外,它确实非常简单:

def get_loss(y_hat, y):
 # No loss on diagonal
 B, N, _ = y_hat.shape
 y_hat[:, torch.arange(N), torch.arange(N)] = torch.finfo(y_hat.dtype).max  # to be "1" after sigmoid

 # calc loss
 loss = F.binary_cross_entropy_with_logits(y_hat, y)  # cross entropy

 y_hat = torch.sigmoid(y_hat)
 tp = (y_hat * y).sum(dim=(1, 2))
 fn = ((1. - y_hat) * y).sum(dim=(1, 2))
 fp = (y_hat * (1. - y)).sum(dim=(1, 2))
 loss = loss - ((2 * tp) / (2 * tp + fp + fn + 1e-10)).sum()  # fscore

return loss

So far I came up with following:到目前为止,我想出了以下内容:

def get_loss(y_hat, y):
 loss = tf.keras.losses.BinaryCrossentropy()(y_hat,y)  # cross entropy (but no logits)


 y_hat = tf.math.sigmoid(y_hat)

 tp = tf.math.reduce_sum(tf.multiply(y_hat, y),[1,2])
 fn = tf.math.reduce_sum((y - tf.multiply(y_hat, y)),[1,2])
 fp = tf.math.reduce_sum((y_hat -tf.multiply(y_hat,y)),[1,2])
 loss = loss - ((2 * tp) / tf.math.reduce_sum((2 * tp + fp + fn + 1e-10)))  # fscore

return loss

so my questions boil down to:所以我的问题归结为:

  • What does torch.finfo() do and how to express it in TensorFlow? torch.finfo()做了什么以及如何在 TensorFlow 中表达它?
  • Does y_hat.dtype just return the data type? y_hat.dtype是否只返回数据类型?

1. What does torch.finfo() do and how to express it in TensorFlow? 1.torch.finfo()是做什么的,在TensorFlow中怎么表达?

.finfo() provides a neat way to get machine limits for floating-point types. .finfo()提供了一种获取浮点类型机器限制的简洁方法。 This function is available in Numpy , Torch as well as Tensorflow experimental .此 function 可用于NumpyTorch以及Tensorflow 实验

.finfo().max returns the largest possible number representable as that dtype. .finfo().max返回可表示为该 dtype 的最大可能数字。

NOTE: There is also a .iinfo() for integer types.注意:还有一个.iinfo()用于 integer 类型。

Here are a few examples of finfo and iinfo in action.以下是finfoiinfo的一些示例。

print('FLOATS')
print('float16',torch.finfo(torch.float16).max)
print('float32',torch.finfo(torch.float32).max)
print('float64',torch.finfo(torch.float64).max)
print('')
print('INTEGERS')
print('int16',torch.iinfo(torch.int16).max)
print('int32',torch.iinfo(torch.int32).max)
print('int64',torch.iinfo(torch.int64).max)
FLOATS
float16 65504.0
float32 3.4028234663852886e+38
float64 1.7976931348623157e+308

INTEGERS
int16 32767
int32 2147483647
int64 9223372036854775807

If you want to implement this in tensorflow, you can use tf.experimental.numpy.finfo to solve this.如果你想在 tensorflow 中实现这个,你可以使用tf.experimental.numpy.finfo来解决这个问题。

print(tf.experimental.numpy.finfo(tf.float32))
print('Max ->',tf.experimental.numpy.finfo(tf.float32).max)  #<---- THIS IS WHAT YOU WANT
Machine parameters for float32
---------------------------------------------------------------
precision =   6   resolution = 1.0000000e-06
machep =    -23   eps =        1.1920929e-07
negep =     -24   epsneg =     5.9604645e-08
minexp =   -126   tiny =       1.1754944e-38
maxexp =    128   max =        3.4028235e+38
nexp =        8   min =        -max
---------------------------------------------------------------

Max -> 3.4028235e+38

2. Does y_hat.dtype just return the data type? 2. y_hat.dtype 是否只返回数据类型?

YES.是的。

In torch, it would return torch.float32 or something like that.在火炬中,它会返回torch.float32或类似的东西。 In Tensorflow it would return tf.float32 or something like that.在 Tensorflow 中,它将返回tf.float32或类似的东西。

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