[英]C++ : pointer on member function
namespace Borg
{
class BorgQueen
{
public:
BorgQueen();
bool move(Borg::Ship *ship, Destination dest) {return ship->move(dest);}
void fire(Borg::Ship *ship, Federation::Starfleet::Ship *target) {ship->fire(target);}
void destroy(Borg::Ship *ship, Federation::Ship *target) {ship->fire(target);}
void (Borg::BorgQueen::*firePtr)(Borg::Ship *ship, Federation::Starfleet::Ship *target) = &Borg::BorgQueen::fire;
void (Borg::BorgQueen::*destroyPtr)(Borg::Ship *ship, Federation::Ship *target) = &Borg::BorgQueen::destroy;
bool (Borg::BorgQueen::*movePtr)(Borg::Ship *ship, Destination dest) = &Borg::BorgQueen::move;
};
};
I need to have a pointers on mebers of my class: movePtr -> move();我需要一个关于我的 class 成员的指针: movePtr -> move(); This is what I have mannage to comme whit but i access it (the pointer);
这是我有办法解决的问题,但我访问了它(指针); how can i call it from the ptr?
我怎样才能从ptr调用它?
int main()
{
Borg::BorgQueen Q();
[...]
// this does work
Q.movePtr(...);
Q.*movePtr(...);
*(Q.movePtr)(...)
}
The right-hand side of .*
is not resolved in the context of the left-hand side, but in the current scope. .*
的右侧不是在左侧的上下文中解析的,而是在当前的 scope 中解析的。
Like this:像这样:
int main()
{
bool (Borg::BorgQueen::*go)(Borg::Ship *ship, Destination dest) = &Borg::BorgQueen::move;
Borg::BorgQueen queen;
//...
(queen.*go)(something something...);
}
Q
is your object, the name of its member is Q.movePtr
, the "dereference pointer-to-member" operator is .*
, so you need Q
是你的 object,它的成员的名字是Q.movePtr
,“解引用成员指针”运算符是.*
,所以你需要
(Q.*Q.movePtr)(...);
Pointers-to-members seem very neat until you notice that they easily make your code completely unreadable.指向成员的指针看起来非常简洁,直到您注意到它们很容易使您的代码完全不可读。
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