如何在 java 中用括号将长 boolean 表达式换行

Question

How to wrap this expression in java for more readability with the constraint that the sub expression (shouldSendSomething(x) && loooongFunctionName1(x) && looooongFunctionName2(x)) inside the paranthesis is too long to fit in a single line?

!(loooongFunctionName0(x) && loooongFunctionName1(x) && looooongFunctionName2(x)) && looooongFunctionName3(x) && looooongFunctionName4(x) && looooongFunctionName5(x)

Answer 1

Maybe having each condition on a new line?

if (!(loooongFunctionName0(x) 
                && loooongFunctionName1(x) 
                && looooongFunctionName2(x)) 
                && looooongFunctionName3(x) 
                && looooongFunctionName4(x) 
                && looooongFunctionName5(x)) {
            
        }

Later Edit: If you have soo many conditions, it usually means that there is a design problem somewhere and maybe some refactoring is needed.

Answer 2

In such cases I would suggest to create some helper methods. Wrap some of the conditions into a single method which will simplify the if condition.

function foo() {
  return bar && baz && qux;
}

And use it in your if condition like:

if (foo()) { ... }

or

if (!foo()) { ... }

Answer 3

I personally prefer to assign the results to a meaningful & short (when possible) variable and then use it inside the if clause

boolean name0 = loooongFunctionName0(x);
boolean name1 = loooongFunctionName1(x);
boolean name2 = loooongFunctionName2(x);
boolean name3 = loooongFunctionName3(x);
boolean name4 = loooongFunctionName4(x);
boolean name5 = loooongFunctionName5(x);

if (!(name1 && name2 && name3 && name4 && name5)) {
   // something
}

Answer 4

According to coding standards in terms of java, max characters in one line can be 80. So here you can wrap it this way:

!(loooongFunctionName0(x) 
    && loooongFunctionName1(x) 
    && looooongFunctionName2(x))
&& looooongFunctionName3(x) 
&& looooongFunctionName4(x) 
&& looooongFunctionName5(x)