[英]How to debug error this File “compiler.py”, line 8 f(n, m+1) = f(n-1, m) + f(n, m) + f(n+1, m) ^ SyntaxError: can't assign to function call
How to debug it?如何调试它?
def f(n, m):
while f(n, m) != int(f(n, m)):
if n == 1:
return 1
elif n >= m - 1:
return 0
elif n >= 2 and n != m - 1:
f(n, m+1) = f(n-1, m) + f(n, m) + f(n+1, m)
print(f(2, 4))
In console it appear error here在控制台中,这里出现错误
File "compiler.py", line 8 f(n, m+1) = f(n-1, m) + f(n, m) + f(n+1, m) ^ SyntaxError: can't assign to function call文件“compiler.py”,第 8 行 f(n, m+1) = f(n-1, m) + f(n, m) + f(n+1, m) ^ SyntaxError: can't assign to function 调用
You are writing你在写
f(n, m+1) = f(n-1, m) + f(n, m) + f(n+1, m)
f(n, m + 1) is not a variable, it's a call for a function. f(n, m + 1) 不是变量,它是对 function 的调用。 I don't know what you are trying to achieve here with this weird code.我不知道你想用这个奇怪的代码在这里实现什么。
I know it now just我现在才知道
def f(n, m):
if n == 1:
return 1
elif n > m:
return 0
else:
return f(n-1, m-1 ) + f(n, m-1 ) + f(n+1, m-1 )
print(f( 98, 100 ))
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