如何在不使用任何系统辅助函数的情况下将 c# 中的 byte[] 转换为 int？

Question

To convert a byte[] to an int, I would normally use BitConverter.ToInt32 , but I'm currently working within a framework called UdonSharp that restricts access to most System methods, so I'm unable to use that helper function. I was able to do the reverse operation manually (converting int to byte[]) quite easily like so:

private byte[] GetBytes(int target)
{
    byte[] bytes = new byte[4];
    bytes[0] = (byte)(target >> 24);
    bytes[1] = (byte)(target >> 16);
    bytes[2] = (byte)(target >> 8);
    bytes[3] = (byte)target;
    return bytes;
}

But I'm struggling to get it working the other way around. Would greatly appreciate any help!

Answer 1

You can check the code here: https://referencesource.microsoft.com/#mscorlib/system/bitconverter.cs

#if BIGENDIAN
        public static readonly bool IsLittleEndian /* = false */;
#else
        public static readonly bool IsLittleEndian = true;
#endif

[System.Security.SecuritySafeCritical] // auto-generated
public static unsafe int ToInt32(byte[] value, int startIndex) {
  if (value == null) {
    ThrowHelper.ThrowArgumentNullException(ExceptionArgument.value);
  }

  if ((uint) startIndex >= value.Length) {
    ThrowHelper.ThrowArgumentOutOfRangeException(ExceptionArgument.startIndex, ExceptionResource.ArgumentOutOfRange_Index);
  }

  if (startIndex > value.Length - 4) {
    ThrowHelper.ThrowArgumentException(ExceptionResource.Arg_ArrayPlusOffTooSmall);
  }
  Contract.EndContractBlock();

  fixed(byte * pbyte = & value[startIndex]) {
    if (startIndex % 4 == 0) { // data is aligned 
      return *((int * ) pbyte);
    } else {
      if (IsLittleEndian) {
        return ( * pbyte) | ( * (pbyte + 1) << 8) | ( * (pbyte + 2) << 16) | ( * (pbyte + 3) << 24);
      } else {
        return ( * pbyte << 24) | ( * (pbyte + 1) << 16) | ( * (pbyte + 2) << 8) | ( * (pbyte + 3));
      }
    }
  }
}