Oracle LISTAGG DISTINCT 与多个条件

Question

For Oracle12, I have the table shown below

ID	CONTACTCODE	CONTACTPERSON
1	X	CLIENT
1	X	CLIENT
1	X	WIFE
1	Y	CLIENT
1	Z	WIFE
1	Z	CLIENT
1	Z	HUSBAND
1	W	CLIENT
2	Y	CHILD
2	Y	WIFE
2	Y	CLIENT
3	Y	HUSBAND
3	W	CLIENT

And I want the result like:

• CONTACTPERSON is CLIENT. If CONTACTCODE in (X,Y,Z) then list all distinct CONTACTCODE ( Ex: X,Y,...) else 0 ( MAIN column)
• CONTACTPERSON <> CLIENT. If CONTACTCODE in (X,Y,Z) then list all distinct CONTACTCODE ( Ex: X,Y,...) else 0 ( REF column)

Expected table:

ID	MAIN	REF
1	X,Y, Z	X,Z
2	Y	Y
3	0	Y

I used row_number partition by ID, CONTACTCODE and then LISTAGG where row_number = 1 but I had many problems.

Answer 1

You can use the distinct , case..when and LISTAGG as follows:

select id, 
       coalesce(listagg(case when isclient = 'CLIENT' then contactcode end,',') 
                  within group (order by contactcode), '0') as maincode,
       coalesce(listagg(case when isclient = 'NOT CLIENT' then contactcode end,',') 
                  within group (order by contactcode), '0') as ref 
(select distinct id, contactcode, 
        case when contactperson = 'CLIENT' then 'CLIENT' else 'NOT CLIENT' end as isclient
  from your_table t
 where t.contactcode in ('X', 'Y', 'Z') ) t
 group by id

Answer 2

You can use row_number() and conditional aggregation:

select id,
       (case when sum(case when contactperson = 'Client' then 1 else 0 end) > 0
             then listagg(case when seqnum = 1 and contactcode in ('X', 'Y', 'Z')
                               then contactcode
                          end, '') within group (order by contactcode)
        end),
       listagg(case when seqnum = 1 and contactcode in ('X', 'Y', 'Z')
                    then contactcode
               end, '') within group (order by contactcode)
from (select t.*,
             row_number() over (partition by id, contactcode order by id) as seqnum
      from t
     ) t
group by id