[英]Typescript: why keyof Union is never
This is my Typescript code:这是我的Typescript代码:
interface Todo {
title: string;
content: string
}
type Union = Omit<Todo, 'content'> | {
name: string
};
type key = keyof Union; // never
My question is that why the type key is never?我的问题是为什么类型键永远不会?
Because extends
works like intersection &
.因为extends
像交集&
一样工作。
interface Todo {
title: string;
content: string
}
// a bit simplified
type A = Omit<Todo, 'content'> // { title: string }
type B = { name: string };
type Union = A | B
type key = keyof Union; // never
keyof
operator checks if union type has any sharable property. keyof
运算符检查联合类型是否具有任何可共享属性。 In your case neither A
nor B
has not same property.在您的情况下, A
和B
都没有相同的属性。
Take a look on next example:看下一个例子:
type A = { name: string, age: number }
type B = { name: string };
type Union = A | B
type key = keyof Union; // name
Here, keyof will return "name".在这里,keyof 将返回“名称”。 because this property exists in both A and B.因为这个属性在 A 和 B 中都存在。
The problem lies in the |
问题出在|
operator.操作员。 If you substitute it with &
, you will get the result you expect:如果你用&
代替它,你会得到你期望的结果:
interface Todo {
title: string;
content: string
}
type Union = Omit<Todo, 'content'> & {
name: string
};
type key = keyof Union; // "title" | "name"
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