如何在每次迭代中更改数组中的值？

Question

I have matrices of different sizes and I try to increase the value in each row with each iteration.

I managed to increase the value in each row, but when the iteration moves to the next matrix, it only increases the value from the first row of the previous matrix I would need it to proceed from the last row of the matrix

Is the way to save the last iteration from the previous matrix and continue the iteration in the next matrix?

here is the part of the code where I iterate the arrays

c1=c1 + 10 * (np.arange(c1.shape[1]) + 1)*p
p +=1

My result

#first iteration
11 12 13 
21 22 23   
#second iteration
21 22 23 
41 42 43 
61 62 63   
#third iteration    
31 32 33 
61 62 63  

I need

11 12 13 
21 22 23   

31 32 33 
41 42 43 
51 52 53   

61 62 63 
71 72 63

This is my full code where reading input from text file

demofile.txt

>=2 1 2 3 
>=3 1 2 3 
>=2 1 2 3

full code

import os
import sys
import numpy as np
import re

f = open("demofile.txt", "r")
lines = f.readlines()
p=1
#sys.stdout = open("results.txt", "w")
for i in list(lines):
     if i[0] != '<' and i[0] != '>' and i[0] != '=':# change txt file for np.array
        p = str(' '.join(i.split())) 
        print(p)
        
     else:
        w = i[3:]
        frst=i[2]
        w = ', '.join(w.split())
        y = i[2]
        y=int(y)+1
        #INSERT input to array
        c=np.array([w])
        c1 = [int(i) for i in c[0].replace(" ", "").split(",")]

        frst=str(frst).replace("[",'')
        frst=str(frst).replace("]",'')
        frst=int(frst)
        c1=np.array(c1)        

        sest2=c1
        c1=np.array([c1]*frst) #frst is the first value by which the matrix is multiplied
        c1=np.transpose(c1)#transpose
        

        #change value every iteration
        c1=c1 + 10 * (np.arange(c1.shape[1]) + 1)*p
        left=c1*-1
        sedem=np.transpose(left)*-1 #transpose matrix
        p +=1
       
        #editing outputs
        sedem=str(sedem).replace("[",'')
        sedem=str(sedem).replace("]",' 0')
        sedem=str(sedem).replace(".",'')
        sedem = sedem[:-1]
        sedem=str(sedem).replace("\n ",'\n')
        sedem=str(sedem).replace("  ",' ')
        sedem=str(sedem).replace("\n ",'\n')
        sedem=str(sedem).lstrip()       
        print(sedem,'\n')

Answer 1

Try this:

        #change value every iteration
        c1 = np.array([[(p + j) * 10 for j in range(frst)]] * 3) + c1
        left=c1*-1
        sedem=np.transpose(left)*-1 #transpose matrix
        p += frst

You track p stepping by frst and make a matrix of elements which are 10's multiples based on p .

For example, if p == 3 , the matrix will be

[[30 40 50]
 [30 40 50]
 [30 40 50]]

Answer 2

Lets try something link this with more usage of numpy to solve the problem. Only use iterator to break the above array into chunks for each input.

You can easily modify your code to get the input from the txt file to a numpy array such that each line in text is a single row in an array.

#Setup each row in text file as a row in a np matrix

arr = np.array([[2,1,2,3],
                [3,1,2,3],
                [2,1,2,3]])

print('INPUT:')
print(arr)
print('')

ones = np.repeat(arr[:,1:], arr[:,0], axis=0)
tens = (np.arange(1,arr[:,0].sum()+1)*10)
nums = ones+tens[:, None]

print('nums:')
print(nums)
print('')

#Splitting nums for each input
l = np.cumsum([0]+list(arr[:,0]))
chunks = [nums[i:j,:] for i,j in zip(l,l[1:])]

print('OUTPUT:')
for i,chunk in enumerate(chunks):
    print('chunk number',i,':')
    print(chunk)
    print('')

INPUT:
[[2 1 2 3]
 [3 1 2 3]
 [2 1 2 3]]

nums:
[[11 12 13]
 [21 22 23]
 [31 32 33]
 [41 42 43]
 [51 52 53]
 [61 62 63]
 [71 72 73]]

OUTPUT:
chunk number 0 :
[[11 12 13]
 [21 22 23]]

chunk number 1 :
[[31 32 33]
 [41 42 43]
 [51 52 53]]

chunk number 2 :
[[61 62 63]
 [71 72 73]]