无法消费 Rgba<u8> （无方法）在 Rust</u8>

Question

let png = image::open("src/heightmaps/ALPSMLC30_N050E014_DSM_8_BIT.png").unwrap();
    for p in png.pixels() {
        let p: image::Rgba<u8> = p.2;
    }

p is (u32, u32, image::Rgba<u8>) . What I don't know is how to access the u8 out of Rgba (the VSCode doesn't find any methods for it). How do I proceed? Here is the link to the Rgba struct: https://docs.rs/image/0.23.13/image/struct.Rgba.html .

Answer 1

image::Rgba is a tuple struct, you can access fields of a tuple struct using struct.0 syntax or more ergonomically through destructuring:

let png = image::open("src/heightmaps/ALPSMLC30_N050E014_DSM_8_BIT.png").unwrap();
for (_, _, image::Rgba(p)) in png.pixels() {
    let [r, g, b, a] = p;
}

Answer 2

Looking at the definition for image::Rgba<T> , it appears that the only field is public so you should be able to just access it directly.

Eg with verbsoe destructuring:

let png = image::open("src/heightmaps/ALPSMLC30_N050E014_DSM_8_BIT.png").unwrap();
for p in png.pixels() {
    let p: image::Rgba<u8> = p.2;
    let rgba: [u8;4] = p.0;
    let [r,g,b,a] = rgba;

}