在使用 try/except 的 while 循环中打印不起作用（Windows ！！！）

Question

Not sure what's wrong here, function's not printing anything (tried '1' as argument i). I've seen an answer suggesting adding flush=True to print, but that doesn't solve the issue. Any hints appreciated, More broadly - should I even be using the try/except framework if I want the function to be keyboard-controled? or is there a better way?

def i_printer(i):
    while True:
        try:
            if keyboard.is_pressed('q'):
                break
        except:
            print(i)
            time.sleep(3)

EDIT: using Windows, apparently keyboard doens't work with it, looking for different solution.

Answer 1

Try and except blocks are used to handle exception. Since you are not going to face any error when clicking 'q', I don't think the usage of them is any good here. Just simple if statement would do the job.

def i_printer(i):
    while True:
        if keyboard.is_pressed('q'):
            break
        print(i)
        time.sleep(3)

EDIT: In case you wanna record keyboard press try this out. The following code will record all the keys except 'q' and print recorded keys.

import keyboard

def i_printer():
    rk = keyboard.record(until ='q') 
    return keyboard.play(rk, speed_factor = 1) 

i_printer()

Answer 2

Got the ball rolling this way, with a generator function and an iterator (using windows, not linux):

import keyboard
import time

def printer():
    while True:
        yield '1'
        time.sleep(1)

def iterator():
    for i in aaa():
        if keyboard.is_pressed('q'):
            break
        else:
            print(i)

iterator()