在 Python3 中运行 linux shell 命令

Question

I am creating a service manager to manage services such as apache, tomcat.. etc. I can enable/disable services by srvmanage.sh enable <service_name> in shell. I want to do this using python script. How to do it?

service_info = ServiceDB.query.filter_by(service_id=service_id).first()
    service_name = service_info.service
    subprocess.run(['/home/service_manager/bin/srvmanage.sh enable', service_name],shell=True)

what is the problem with this code?

Answer 1

I'm guessing if you want to do this in python you may want more functionality. If not @programandoconro answer would do. However, you could also use the subprocess module to get more functionality. It will allow you to run a command with arguments and return a CompletedProcess instance. For example

import subprocess

# call to shell script
process = subprocess.run(['/path/to/script', options/variables], capture_output=True, text=True)

You can add in additional functionality by capturing the stderr/stdout and return code. For example:

# call to shell script
process = subprocess.run(['/path/to/script', options/variables], capture_output=True, text=True)
  
# return code of 0 test case. Successful run should return 0
if process.returncode != 0:
    print('There was a problem')
    exit(1)

Docs for subprocess is here

Answer 2

You can use os module to access system commands.

import os

os.system("srvmanage.sh enable <service_name>")

Answer 3

I fixed this issue.

operation = 'enable'
    service_operation_script = '/home/service_manager/bin/srvmanage.sh'
    service_status = subprocess.check_output(
       "sudo " +"/bin/bash " + service_operation_script + " " + operation + " " + service_name, shell=True)
    response = service_status.decode("utf-8")
    print(response)