有没有办法清除 LWJGL 的 memory 的颜色？

Question

I am creating a 2D game where I am currently drawing on the screen, a quad filling the entire screen to have a blue background. Then I am drawing a stone texture on top of it. The issue is when the program draws the stone, it gives it a blue tint as it is using the colour from the sky quad. I was wondering if there is a way to clear the colour from the memory of OpenGL / GLFW / LWJGL. I am using Java 1.8 and LWJGL 3.2.3

Here is the code:

private static void renderAir() {
        glfwMakeContextCurrent(InnocentDream.win);
        glBegin(GL_QUADS);
        glColor4f(0, 204 / 255f, 1, 1);
        glVertex2f(-256, 128);
        glColor4f(0, 204 / 255f, 1, 1);
        glVertex2f(256, 128);
        glColor4f(0, 108 / 255f, 250 / 255f, 1);
        glVertex2f(256, -128);
        glColor4f(0, 108 / 255f, 250 / 255f, 1);
        glVertex2f(-256, -128);
        glEnd();
}

I have the GLFW and GL11 classes as static imports.

public void renderTileAtPos(float x, float y) {
        float TILE_WIDTH = Tile.TILE_WIDTH / 2f;
        glEnable(GL_TEXTURE_2D);
        glBindTexture(GL_TEXTURE_2D, texture.getTextureID());
        glBegin(GL_QUADS);
        glTexCoord2f(1, 0);
        glVertex2f(-TILE_WIDTH + x, TILE_WIDTH + y);
        glTexCoord2f(0, 0);
        glVertex2f(TILE_WIDTH + x, TILE_WIDTH + y);
        glTexCoord2f(0, 1);
        glVertex2f(TILE_WIDTH + x, -TILE_WIDTH + y);
        glTexCoord2f(1, 1);
        glVertex2f(-TILE_WIDTH + x, -TILE_WIDTH + y);
        glEnd();
        glDisable(GL_TEXTURE_2D);
}

And here is the tile rendering.

Answer 1

glColor4f(1,1,1,1);

Throw that call either after your original sky code, or just before you render the stone.

It's a good practice if using glColor() calls, to get in the habit of always calling glColor() before drawing anything, or to only call it once on initialisation and never call it again.

There is no "remove the colour I just set" call. The value of "glColor" is just one of those pieces of state that OpenGL hangs on to.