[英]Use object values as interface keys
I have an object containing property names in the form:我有一个包含以下形式的属性名称的 object:
const INPUT_NAMES = {
FIRST_NAME: 'first-name',
LAST_NAME: 'last-name'
};
I want to generate an interface based on those property name values:我想根据这些属性名称值生成一个接口:
interface IPropertyFormat {
[INPUT_NAMES.FIRST_NAME]: string;
[INPUT_NAMES.LAST_NAME]: string;
}
That doesn't work because I am not using a literal type, nor a symbol and I get this: A computed property name in an interface must refer to an expression whose type is a literal type or a 'unique symbol' type.
这不起作用,因为我没有使用文字类型,也没有使用符号,我得到了这个:
A computed property name in an interface must refer to an expression whose type is a literal type or a 'unique symbol' type.
Using a simple constant like:使用一个简单的常量,如:
const KEY = "FIRST_NAME";
interface IPropertyFormat {
[KEY]: string;
}
works but is not an elegant solution in my case and would like to avoid it if possible.有效,但在我的情况下不是一个优雅的解决方案,如果可能的话,我想避免它。 I've checked out this other kinda related topic but it doesn't provide a solution for my problem.
我已经检查了这个其他有点相关的主题,但它没有为我的问题提供解决方案。
Anyone has any idea how to work around this problem?任何人都知道如何解决这个问题?
EDIT:编辑:
Also, found a "some-what" solution at this post once again using const assertions .此外,在这篇文章中再次使用const assertions找到了一个“有点什么”的解决方案。
To have the correct litteral types in INPUT_NAMES
you should use as const
要在
INPUT_NAMES
中拥有正确的文字类型,您应该使用as const
const INPUT_NAMES = {
FIRST_NAME: 'first-name' as const,
LAST_NAME: 'last-name' as const
};
type Result = {
[k in typeof INPUT_NAMES[keyof typeof INPUT_NAMES]]: string
}
type Expected = {
'first-name': string,
'last-name': string
}
declare const x: Expected
declare const y: Result
// In case Result and Expected are different types, there will be an error
const a: Expected = y
const b: Result = x
If having an interface is very important:如果有一个接口很重要:
interface myInterface extends Result {}
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