是否有 C# 速记将值转换为其方法的返回类型？

Question

Is there shorthand in C# for casting a value to its method's return type? For example, in this method, is there a shorthand way to cast the return value of GetInt's to its return type of 'int', instead of discretely typing out 'int'?

I know this is a really simple example, and many of you are going to say "it's easier to just put (int) there" but it would be really great syntactic sugar for some things I'm trying to do if this is possible. It would be very similar to the 'default' keyword shorthand that already exists.

// Return type of SomeFunc cannot be changed by me
object SomeFunc();

public int GetInt()
{
    object Value = SomeFunc();
    // I know "Value" should be of type "int" here.
    return ({ReturnType})Value;
}

Answer 1

Does such a feature exist? None that I am aware of.

Can you add such syntactic sugar somehow? Probably yes , but none of the options are going to be simpler than an explicit cast. You may lose some IDE features. You'll probably go against good practices. I imagine that things like Reflection, Decorators, dynamic types, switch expressions , etc may be of use here.

Implicit conversions? You can always use a derived class implicitly converted to any of its base class. Some helpful links - casting-and-type-conversions , user-defined-conversion-operators , type-testing-and-cast

If you are sure that your object is castable safely, you can use alternate syntax which doesn't throw an exception , Value as int

At the end of the day, none of this needs to be considered first, unless one has a use case where it could help them BIG TIME . Syntactic sugar is not even close to that use case IMO, especially for a statically typed language.

Answer 2

I can think of using generics (it won't work with int, but will with custom type):

public class Foo { }

public static object Value = null;
public static T GetFoo<T>() where T : Foo
{
    return (T)Value;
}