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C#反射:特定类型的对象列表中的类型转换方法返回值

[英]C# Reflection : Type cast method return value in specific type of object list

I have following assemble which contains following data 我有以下汇编,其中包含以下数据

demo.dll

Class 1 1类

namespace demo

public class Data
{
    public string FirstName {get; set;}
}

Class 2 2级

namespace demo

public class Utility
{
   private List<Data> items;

   public Utility()
   {
      items = new List<Data>();
      items.add(new Data(){ FirstName = "Abc" });
   }

   public List<Data> GetItems()
   {
       return items;
   }
}

Now I want to load above demo.dll assemble using runtime and call GetItem() method. 现在,我想使用运行时加载以上demo.dll组装并调用GetItem()方法。

For that I can write following code 为此,我可以编写以下代码

Assembly assembly = Assembly.LoadFile(Path.Combine(Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location) ,"demo.dll"));

Type Utility= assembly.GetType("demo.Utility");
Type Data= assembly.GetType("demo.Data");

MethodInfo GetItems = Utility.GetMethod("GetItems");

object utility = Activator.CreateInstance(Utility);

object returnValue = GetItems.Invoke(utility, null);

Now I want to type cast above returnValue in List of type Data and access the FirstName property. 现在,我要在数据类型的列表中的returnValue上键入returnValue类型转换,并访问FirstName属性。

How can I achieve this using reflection? 如何使用反射实现此目的?

Assuming that everything you wrote works then 假设您编写的所有内容都可以正常工作

object returnValue = GetItems.Invoke(utility, null);

returnValue is actually a List<Data> , but you can't cast it, because at compile time the compiler doesn't have the type information of the Data class. returnValue实际上是一个List<Data> ,但是您不能进行强制转换,因为在编译时,编译器没有Data类的类型信息。 But since a List<T> implements IList you can cast to that and iterate over its items ( IEnumerable<object> should work too). 但是由于List<T>实现了IList您可以将其强制转换并对其项进行迭代( IEnumerable<object>应起作用)。

Then you can use reflection again to access the FirstName property: 然后,您可以再次使用反射来访问FirstName属性:

var returnValue = (IList)GetItems.Invoke(utility, null);

foreach (var item in returnValue)
{
    var type = item.GetType();
    var property = type.GetProperty("FirstName");
    var firstName = property.GetValue(item);
}

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