如何更改路径的文件名而不更改其目录或扩展名？

Question

What's the best way to implement the change_file_name function?

let path = Path::new("/path/to/file.rs");
let new_path = change_file_name(&path, "new_file_name") // -> "/path/to/new_file_name.rs"

Answer 1

Take something that can be referenced as a Path , then pop off the existing filename, replacing it and preserving the optional extension:

use std::path::{Path, PathBuf};

fn change_file_name(path: impl AsRef<Path>, name: &str) -> PathBuf {
    let path = path.as_ref();
    let mut result = path.to_owned();
    result.set_file_name(name);
    if let Some(ext) = path.extension() {
        result.set_extension(ext);
    }
    result
}

fn main() {
    let path = "/path/to/file.rs";
    let new_path = change_file_name(path, "new_file_name");
    assert_eq!(new_path, Path::new("/path/to/new_file_name.rs"));
}

See also:

• How to get only the directory portion of the current executable's path?
• Replacing Path parts in Rust
• Best way to format a file name based on another path in Rust
• Extracting a file extension from a given path in Rust idiomatically
• How do I replace the file extension of a PathBuf or Path?