对 dataframe 中的每两列应用 function 并用 output 替换原始列

Question

I have a dataframe that contains X & Y data in columns like this:

df_cols = ['x1', 'y1', 'x2', 'y2', 'x3', 'y3']

np.random.seed(365)
df = pd.DataFrame(np.random.randint(0,10,size=(10, 6)), columns=df_cols)

   x1  y1  x2  y2  x3  y3
0   2   4   1   5   2   2
1   9   8   4   0   3   3
2   7   7   7   0   8   4
3   3   2   6   2   6   8
4   9   6   1   6   5   7
5   7   6   5   9   3   8
6   7   9   9   0   1   4
7   0   9   6   5   6   9
8   5   3   2   7   9   2
9   6   6   3   7   7   1

I need to call a function that takes one X & Y pair at a time and returns and updated X & Y pair (same length), and then either save that data to a new dataframe with the original column names, or replace the old X & Y data with the new data and keep the original column names.

For example, take this function below:

def samplefunc(x, y):
    x = x*y
    y = x/10
    return x, y

# Apply function to each x & y pair 
x1, y1 = samplefunc(df.x1, df.y1)
x2, y2 = samplefunc(df.x2, df.y2)
x3, y3 = samplefunc(df.x3, df.y3)

 # Save new/updated x & y pairs into new dataframe, preserving the original column names 
df_updated = pd.DataFrame({'x1': x1, 'y1': y1, 'x2': x2, 'y2': y2, 'x3': x3, 'y3': y3})

# Desired result:
In [36]: df_updated
Out[36]: 
   x1   y1  x2   y2  x3   y3
0   8  0.8   5  0.5   4  0.4
1  72  7.2   0  0.0   9  0.9
2  49  4.9   0  0.0  32  3.2
3   6  0.6  12  1.2  48  4.8
4  54  5.4   6  0.6  35  3.5
5  42  4.2  45  4.5  24  2.4
6  63  6.3   0  0.0   4  0.4
7   0  0.0  30  3.0  54  5.4
8  15  1.5  14  1.4  18  1.8
9  36  3.6  21  2.1   7  0.7

But doing it this way is obviously really tedious and impossible for a huge dataset. The similar/related questions I've found perform a simple transformation on the data rather than calling a function, or they add new columns to the dataframe instead of replacing the originals.

I tried to apply @PaulH's answer to my dataset, but neither of them are working as it is unclear how to actually call the function inside of either method.

# Method 1
array = np.array(my_actual_df)
df_cols = my_actual_df.columns
dist = 0.04 # a parameter I need for my function 
df = (
    pandas.DataFrame(array, columns=df_cols)
        .rename_axis(index='idx', columns='label')
        .stack()
        .to_frame('value')
        .reset_index()
        .assign(value=lambda df: numpy.select(
            [df['label'].str.startswith('x'), df['label'].str.startswith('y')],

            # Call the function (not working): 
            [df['value'], df['value']] = samplefunc(df['value'], df['value']),
        ))
        .pivot(index='idx', columns='label', values='value')
        .loc[:, df_cols]
)



# Method 2
df = (
    pandas.DataFrame(array, columns=df_cols)
        .pipe(lambda df: df.set_axis(df.columns.map(lambda c: (c[0], c[1])), axis='columns'))
        .rename_axis(columns=['which', 'group'])
        .stack(level='group')
         
        # Call the function (not working)
        .assign(df['x'], df['y'] = samplefunc(df['x'], df['y']))
        .unstack(level='group')
        .pipe(lambda df: df.set_axis([''.join(c) for c in df.columns], axis='columns'))
)

The actual function I need to call is from Arty's answer to this question: Resample trajectory to have equal euclidean distance in each sample

Answer 1

Use slicing and apply operations on those slices.

def samplefunc(x, y):
    x = x**2
    y = y/10
    return x, y

arr = df.to_numpy().astype(object) 
e_col = arr[:, ::2]
o_col =  arr[:, 1::2]
e_col, o_col = samplefunc(e_col, o_col)
arr[:, ::2] = e_col 
arr[:, 1::2] = o_col 
out = pd.DataFrame(arr, columns=df.columns)

   x1   y1  x2   y2  x3   y3
0   4  0.4   1  0.5   4  0.2
1  81  0.8  16  0.0   9  0.3
2  49  0.7  49  0.0  64  0.4
3   9  0.2  36  0.2  36  0.8
4  81  0.6   1  0.6  25  0.7
5  49  0.6  25  0.9   9  0.8
6  49  0.9  81  0.0   1  0.4
7   0  0.9  36  0.5  36  0.9
8  25  0.3   4  0.7  81  0.2
9  36  0.6   9  0.7  49  0.1

Answer 2

There are couple of ways you could do this, depending on how your real-life dataframe is constructed.

The first thing that comes to my mind is to fully stack the dataframe and the use numpy.select to compute your new values based on the labels' values. You can then pivot the dataframe back to its original form:

import numpy
import pandas

df_cols = ['x1', 'y1', 'x2', 'y2', 'x3', 'y3']


numpy.random.seed(365)
array = numpy.random.randint(0, 10, size=(10, 6))
df = (
    pandas.DataFrame(array, columns=df_cols)
        .rename_axis(index='idx', columns='label')
        .stack()
        .to_frame('value')
        .reset_index()
        .assign(value=lambda df: numpy.select(
            [df['label'].str.startswith('x'), df['label'].str.startswith('y')],
            [df['value'] ** 2, df['value'] / 10],
        ))
        .pivot(index='idx', columns='label', values='value')
        .loc[:, df_cols]
)

label    x1   y1    x2   y2    x3   y3
idx                                   
0       4.0  0.4   1.0  0.5   4.0  0.2
1      81.0  0.8  16.0  0.0   9.0  0.3
2      49.0  0.7  49.0  0.0  64.0  0.4
3       9.0  0.2  36.0  0.2  36.0  0.8
4      81.0  0.6   1.0  0.6  25.0  0.7
5      49.0  0.6  25.0  0.9   9.0  0.8
6      49.0  0.9  81.0  0.0   1.0  0.4
7       0.0  0.9  36.0  0.5  36.0  0.9
8      25.0  0.3   4.0  0.7  81.0  0.2
9      36.0  0.6   9.0  0.7  49.0  0.1

Alternatively, you could look at your column names as hierarchies, turn it into a multi-level index, and then stack only the second level of that index. That way, you end up with separate x- and y-column that you can operate on directly and explicitly

df = (
    pandas.DataFrame(array, columns=df_cols)
        .pipe(lambda df: df.set_axis(df.columns.map(lambda c: (c[0], c[1])), axis='columns'))
        .rename_axis(columns=['which', 'group'])
        .stack(level='group')
        .assign(x=lambda df: df['x'] ** 2, y=lambda df: df['y'] / 10)
        .unstack(level='group')
        .pipe(lambda df: df.set_axis([''.join(c) for c in df.columns], axis='columns'))
)

Answer 3

New approach here:

• split the column into a multilevel index
• do a horizontal groupby
• modify your samplefunc to take a dataframe:

def samplefunc(df, xcol='x', ycol='y'):
    x = df[xcol].to_numpy()
    y = df[ycol].to_numpy()
    
    df[xcol] = x * y
    df[ycol] = x / 10
    return df

df = (
    pandas.DataFrame(array, columns=df_cols)
        .pipe(lambda df: df.set_axis(df.columns.map(lambda c: (c[0], c[1])), axis='columns'))
        .rename_axis(columns=['which', 'group'])
        .groupby(level='group', axis='columns')
        .apply(samplefunc)
        .pipe(lambda df: df.set_axis([''.join(c) for c in df.columns], axis='columns'))
)

And I get:

   x1   y1  x2   y2  x3   y3
0   8  0.8   5  0.5   4  0.4
1  72  7.2   0  0.0   9  0.9
2  49  4.9   0  0.0  32  3.2
3   6  0.6  12  1.2  48  4.8
4  54  5.4   6  0.6  35  3.5
5  42  4.2  45  4.5  24  2.4
6  63  6.3   0  0.0   4  0.4
7   0  0.0  30  3.0  54  5.4
8  15  1.5  14  1.4  18  1.8
9  36  3.6  21  2.1   7  0.7