遍历用户输入和C中的多维arrays

Question

I am trying to make a code where a user has 5 tries to guess a number and if any of the 3 series of numbers within Winning_order then both of the for loops will break. The usersInputs stores the users inputs to be compared with Winning_order . So for example, if the number 1,2,3 or 1,2,4,5,3 is inputted by the user the loop will print There is a Correlation and the for loops will stop. If the input is 7,8,9,3,2 since no 3 numbers are present within the Winning_order the loops will just stop. There is a problem with the match_arrays function and I do not know how to go about stopping the nested for loops if the if statement is valid.

Checking if the function has a correlation

int match_arrays(int *arr1, int *arr2, int len) {
  for (int p = 0; p < len; p++) {
    if (arr1[p] != arr2[p]) {
      return 0;
    }
  }
  return 1;
}

main() function

int main(void)
{
    int Winning_order[3][3] = {{1,2,3}, {1,4,7}, {2,5,8}};
    int input = 0;
    int usersInputs[5] = {0};
    for (int i = 0; i <= 4; i++){
           printf("\nPlayer input: ");

           scanf("%d", &input);
           usersInputs[i] = input;
           for (int p = 0; p < 5; p++) {
                if (match_arrays(usersInputs, Winning_order[p], 3)) {printf("There's a Corelation");}
    }}
    return 0;
}

Answer 1

There are different ways of approaching breaking a double loop (or to generalize: a nested loop), this solution is not the optimal, the best, or the recommended, but it works. I fixed the indentation and some naming issues, but I won't fix anything else.

This is a working snippet:

#include <stdio.h>

int match_arrays(int *arr1, int *arr2, int len) {
  for (int p = 0; p < len; p++) {
    if (arr1[p] != arr2[p]) {
      return 0;
    }
  }
  return 1;
}

int main(void) {
  int winning_order[3][3] = {{1,2,3}, {1,4,7}, {2,5,8}};
  int input = 0;
  int users_inputs[5] = {0};
  for (int i, break_i = 0; !break_i && i < 5; i++){
    printf("\nPlayer input: ");
    scanf("%d", &input);
    users_inputs[i] = input;
    for (int p = 0; p < 3; p++) {
      if (match_arrays(users_inputs, winning_order[p], 3)) {
        printf("There's a Corelation\n");
        break_i = 1;
        break;
      }
    }
  }
  return 0;
}

I made this easy for you to understand. I added a new flag to the outer for loop called break_i with an initial falsy value. Simultaneously, I added a short circuit && operation to the for loop.

Inside your inner loop, I added a break_i = 1 statement that will make the outer loop stop. Immediately after that, I use the break statement to break the inner loop.

---

PS: I also fixed the index out of bounds pointed out by @kaylum. You may want to use a macro or sizeof() next time, but that's beyond the scope of your question.