在链表 c++ 中打印 Function

Question

this is what I'm coding:

template<typename T>
inline void LinkList<T>::print() const
{
    for (Iterator<int> iter = begin(); iter != end(); ++iter)
    {
        std::cout << *iter << std::endl;
    }
    return;
}

and it's saying that this line:

(Iterator<int> iter = begin(); iter != end(); ++iter)

has this error:

`const Iterator<T> LinkList<T>::begin(void)' cannot convert `this` pointer from `const LinkList<int>` to `LinlList<int>&`

By the way:

template<typename T>
inline const Iterator<T> LinkList<T>::begin()
{
    return m_first;
}

template<typename T>
inline const Iterator<T> LinkList<T>::end()
{
    return m_last;
}

this is so that I can print out what I have in my list. This is for class so I HAVE to have it like this.

Edit: so I did everything y'all suggested to do but it gave me errors so i went back to my original code, now i have different errors: /

this is for begin(); and end();

return :cannot convert from Node<T> to Iterator<T>

I don't exactly know what other information y'all need to help y'all out.the values for m_last and m_first is a Node

everyone in my class seems to have the same issue however apparently the code does have a right answer because the teacher has a working code.

I solved the question!!!

template<typename T>
inline const Iterator<T> LinkList<T>::begin()
{
    Node<T> *m_first;
    return m_first;
}

template<typename T>
inline const Iterator<T> LinkList<T>::end()
{
    Node<T>* m_last;
    return m_last;
}

granted i don't know if it works the way it is intended yet!

Answer 1

Your begin() and end() functions are not const therefore they cannot be invoked on const instances of LinkList<T> . If you change your begin and end functions as follows:

template<typename T>
inline const Iterator<T> LinkList<T>::begin() const
{
    return m_first;
}

template<typename T>
inline const Iterator<T> LinkList<T>::end() const
{
    return m_last;
}

You should be fine.

Alternatively, you can make your print function non-const but I do not recommend that. Print functions should not modify the object and so const on the print function makes sense.