SQL 加入另一个字段中包含的属性值

Question

I would like to perform a join on attr_1 and attr_2 when:

• attr_1 = attr_2
• attr_1 is contained in attr_2

A good match is performed if attr_1 is one of the value of attr_2 separated by '/'.

attr_1	attr_2
SOR:562	ACCU:5698A/SOR:22/SOR:562
SOR:120	SOR:120/SOR:125
SOR:89	SOR:1001/ACCU:569/SOR:56239/SOR:89

But I don't want those matches as SOR:89 and SOR:899912 because it's not the same value (89 != 899912)

attr_1	attr_2
SOR:89	SOR:899912

How could I avoid wrong matches? (I tried this but it doesnt work:

on t.attr_1 LIKE CONCAT('%',s.attr_2,'%') )

Answer 1

Instead of

on t.attr_1 LIKE CONCAT('%',s.attr_2,'%')

I think what you are trying to get is

on t.attr_2 LIKE CONCAT('%',s.attr_1,'%')

Answer 2

Convert the second attribute to an array:

select *
from first_table t1
  join second_table t2 on t1.attr1 = any(string_to_array(t2.attr2, '/'))

Answer 3

The condition should be:

ON CONCAT('/', attr_2, '/') LIKE CONCAT('%/', attr_1, '/%')

See a simplified demo .