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如何合并子数组中的对象,以便在 javascript 中剩下一个数组和多个对象

[英]How to merge objects in a subArray such that there is one array left with multiple objects in javascript

I have the following array seen in full at ARRAY 1 , I need each subarray to merge the objects within it such that it is like so.我在 ARRAY 1处完整看到了以下数组,我需要每个子数组来合并其中的对象,使其像这样。

ARRAY FINAL数组最终


[
  {"col0":"glasses","col1":"Milky glasses","col2":"292516467012796941"}
  , ...
]

So the end result is one array with 6 objects.所以最终结果是一个包含 6 个对象的数组。 The... above represents the rest of the objects.上面的...代表对象的rest。

I have tried [].concat.apply([], array) but it doesn't do quite what I want.我已经尝试过[].concat.apply([], array)但它并没有完全达到我想要的效果。 I will post what it does below this array at ARRAY 2我将在 ARRAY 2 的此数组下方发布它的作用

ARRAY 1阵列1

[
  [
    {
      "col0": "Glasses"
    },
    {
      "col1": "Milky Glasses"
    },
    {
      "col2": "292516467012796941"
    }
  ],
  [
    {
      "col0": "Knives"
    },
    {
      "col1": "Milky Knives"
    },
    {
      "col2": "292516484536599049"
    }
  ],
  [
    {
      "col0": "Forks"
    },
    {
      "col1": "Milky Forks"
    },
    {
      "col2": "292516497196057096"
    }
  ],
  [
    {
      "col0": "Gloves"
    },
    {
      "col1": "Kewl Gloves"
    },
    {
      "col2": "292534063457108493"
    }
  ],
  [
    {
      "col0": "Wrench"
    },
    {
      "col1": "Kewl Wrench"
    },
    {
      "col2": "292534088244396552"
    }
  ],
  [
    {
      "col0": "Monkey snake"
    },
    {
      "col1": "Kewl Monkey snake"
    },
    {
      "col2": "292534109863936521"
    }
  ]
]

This is the output that I don't want, but all I could manage thus far.这是我不想要的 output,但到目前为止我能做到的。 See the output I do want at the top at ARRAY FINAL请参阅我想要的 output 在 ARRAY FINAL 的顶部

ARRAY 2阵列 2

[
  {
    "col0": "Glasses"
  },
  {
    "col1": "Milky Glasses"
  },
  {
    "col2": "292516467012796941"
  },
  {
    "col0": "Knives"
  },
  {
    "col1": "Milky Knives"
  },
  {
    "col2": "292516484536599049"
  },
  {
    "col0": "Forks"
  },
  {
    "col1": "Milky Forks"
  },
  {
    "col2": "292516497196057096"
  },
  {
    "col0": "Gloves"
  },
  {
    "col1": "Kewl Gloves"
  },
  {
    "col2": "292534063457108493"
  },
  {
    "col0": "Wrench"
  },
  {
    "col1": "Kewl Wrench"
  },
  {
    "col2": "292534088244396552"
  },
  {
    "col0": "Monkey snake"
  },
  {
    "col1": "Kewl Monkey snake"
  },
  {
    "col2": "292534109863936521"
  }
]

Thanks for any help ahead of time感谢您提前提供任何帮助

You could map the array and spread the objects for getting a single object.您可以 map 数组并传播对象以获得单个 object。

 const data = [[{ col0: "Glasses" }, { col1: "Milky Glasses" }, { col2: 292516467012796900 }], [{ col0: "Knives" }, { col1: "Milky Knives" }, { col2: 292516484536599040 }], [{ col0: "Forks" }, { col1: "Milky Forks" }, { col2: 292516497196057100 }], [{ col0: "Gloves" }, { col1: "Kewl Gloves" }, { col2: 292534063457108500 }], [{ col0: "Wrench" }, { col1: "Kewl Wrench" }, { col2: 292534088244396540 }], [{ col0: "Monkey snake" }, { col1: "Kewl Monkey snake" }, { col2: 292534109863936500 }]], result = data.map(a => Object.assign({}, ...a)); console.log(result);
 .as-console-wrapper { max-height: 100%;important: top; 0; }

That could be accomplished like so, with arr being your original array -这可以像这样完成, arr是您的原始数组 -

for (let i = 0; i < arr.length; i++) {
  let res = {}, subArr = arr[i];
  subArr.forEach((a,ind) => {
Object.assign(res,subArr[0],subArr[1],subArr[2]);
  });
  arr[i] = res;
}

Nina has the best answer, but it's worth noting that Object.assign() is a shallow copy. Nina 有最好的答案,但值得注意的是 Object.assign() 是浅拷贝。

If the col properties were objects themselves you could use an approach like the one below:如果 col 属性本身就是对象,则可以使用如下方法:

const finish = start.map((x) => ({
  ...x[0],
  ...x[1],
  ...x[2]
}));

If I understand correctly, the...x[0] syntax creates a deep copy of x[0] and we assign that directly to our new object, whereas Object.assign() creates a shallow copy.如果我理解正确,...x[0] 语法会创建 x[0] 的深层副本,我们将其直接分配给新的 object,而 Object.assign() 创建浅层副本。

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