使用 awk 将包含制表符和“/”分隔符的 output 分隔为分隔格式

Question

I'll appreciate help in converting this output to a pipe delimited

I have the following output

abcde1234 /path/A/file1
test23455 /path/B/file2345

But I would like in

abcde1234|file1
test23455|file2345

Answer 1

In awk , If you set FS as [[:blank:]]+/|/ you can print the first and last fields:

awk -v FS='[[:blank:]]+/|/' -v OFS='|' '{print $1, $NF}' file
abcde1234|file1
test23455|file2345

Answer 2

Here is a one-liner awk solution:

awk -v FS='[ \t].*/' -v OFS='|' '{$1=$1}1' file

and, a sed one-liner:

sed 's%[[:blank:]].*/%|%' file

and a pure bash one

while read -r; do echo "${REPLY%%[[:blank:]]*}|${REPLY##*/}"; done < file

Answer 3

try to use cut ♀️.

abcde1234 /path/A/file1
test23455 /path/B/file2345

while IFS= read -r line; do
  value1=$(echo $line | cut -d ' ' -f1)
  value2=$(echo $line | cut -d '/' -f4)
  printf "$value1 $value2\n"
done < <(cat list)