'double' 和 'int' 类型的无效操作数到二进制 'operator%'

Question

There !

In one of the my project i am trying to print Float value on seven segment display using Arduino Mega2560 with given codes, But i am getting correct data with decimal values but now when i am trying to print float values unfortunately getting the error as mentioned on title.

Float value's code which i am trying to compile

switch (current_digit)
{
case 1:
 disp(fmodf (adc_value, 10000000));   //8   
 digitalWrite(digit_7, HIGH);  
 break;
 
case 2:
 disp(fmodf (adc_value, 1000000)% 10);   //7
 digitalWrite(digit_6, HIGH);  
 break;
 
case 3:
 disp(fmodf (adc_value, 100000)% 10);   //6
 digitalWrite(digit_5, HIGH);  
 break;
 
case 4:
 disp(fmodf (adc_value, 10000)% 10);   //5
 digitalWrite(digit_4, HIGH);  
 break;
  
case 5:
  disp(fmodf (adc_value, 1000)% 10); //4  
  digitalWrite(digit_3, HIGH); 
   digitalWrite(SegGDP,LOW); 
  break;

case 6:
  disp( fmodf (adc_value, 100) % 10);  //3 
  digitalWrite(digit_2, HIGH);        
  break;

case 7:
  disp( fmodf (adc_value, 10) % 10);   //2
  digitalWrite(digit_1, HIGH);   
  break;

case 8:
  disp(fmodf (adc_value, 10));   //1
  digitalWrite(digit_0, HIGH);  
}

References:

1. Float value references

2. Invalid operands of type 'double' and 'int' to binary 'operator%'

Answer 1

fmodf returns a float. So

fmodf(adc_value, 1000000)% 10

will still attempt float % int .

However, that code does probably not what you want it to do. The equivalent of

(adc_value / 1000000) % 10

should be

fmodf(adc_value / 1000000.f, 10.f)

Answer 2

case 1:
 disp(fmodf (adc_value, 10000000));   //8   

You want floor(adc_value / 10000000) instead, which would be the float equivalent of the integer division adc_value / 10000000 .

case 2:
 disp(fmodf (adc_value, 1000000)% 10);   //7

There is no % between a floating point value and an integer, so here is where you want fmodf as in fmodf ( floor(adc_value / 1000000), 10) .