将字典转换为元组并以相反的顺序打印

Question

I am having values in dict for example {"AR":True,"VF":False,"Siss":True}

Now I am only extracting the keys having value TRUE, so I am only getting the output AR and Siss, I am trying to save this output in tuple and now wants to print them out in reverse order like ("Siss","AR").

Below is my code snippet, When I convert it into tuple its showing me output in form of character instead of string

for i in dic:
        if dic[i]==True:
            t = tuple(i)
            print (t)
            Reverse(t)
def Reverse(tuples): 
    new_tup = tuples[::-1] 
    return new_tup 

How to change those characters into words/strings?

Answer 1

You can do it easily by transverse the dictionary in reversed order and filter out the non True values.

d = {'AR': True, 'VF': False, 'Siss': True}
print(tuple(k for k,v in reversed(d.items()) if v is True))

('Siss', 'AR')

Answer 2

A functional approach:

dictionary = { "AR": True, "VF": False, "Siss": True }
filtered = filter(lambda kv: kv[1], reversed(dictionary.items()))
just_key = map(lambda kv: kv[0], filtered)

print(list(just_key))

It works by:

1. reversed -ing the key-value pairs in the dictionary
2. filter ing the dictionary's items, removing all the key-value pairs that are False .
3. Just preserving the key with a map

Answer 3

Here is a simple step-wise approach that uses a list as an intermediate, fills it with the appropriate keys from your dictionary, reverses the list, then converts it into a tuple.

dic = {"AR":True,"VF":False,"Siss":True}

lst = []
for key in dic:
        if dic[key]: (# ==True is redundant)
            lst.append(key)

lst.reverse()
result = tuple(lst)

print(result)
#('Siss', 'AR')