从文件路径 c++ 中删除文件名

Question

So I have this code that removes the filename from the filepath, but how do I do the opposite ie remove everything except the filename?

sd::string filename = "C:\\Testdir\\file.exe";
const size_t last_slash_idx = filepath_modify.rfind('\\');
if (std::string::npos != last_slash_idx) {
    filepath_modify = filepath_modify.substr(0, last_slash_idx);
};

So if I have this filepath "C:\\Testdir\\file.exe" it will become "file.exe" .

How would I get everything except the filename?

Answer 1

Use the <filesystem> header:

#include <filesystem>
#include <string>
std::filesystem::path filepath{"C:\\Testdir\\file.exe"};
std::string filename = filepath.filename();
//"file.exe"
std::string folderpath = filepath.parent_path();
//"C:\\Testdir\\"

Answer 2

I found a solution

std::string filepath = "C:\\Testdir\\file.exe";
const size_t last_slash_idx = filepath.rfind('\\', filepath_modify.length());
if (std::string::npos != last_slash_idx) {
    filepath =filepath.substr(last_slash_idx + 1, filepath.length() - last_slash_idx);
};