在 python 中将日期从 DD/MM/YYYY HH.mm.ss 转换为 MM-DD-YYYY HH:MM:SS 时出错

Question

I have a dataset which has a column "timestamp" in the Italian format: 11/03/2004 00.00.00 and I need to convert it as 2004-03-11 00:00:00 . I followed the guide on this old post but when I try to do this:

for index, row in dataset.iterrows():
   d = datetime.strptime(row['timestamp'], '%d/%m/%y %H.%M.%S')
   row['timestamp'] = d.strftime('%y-%m-%d %H:%M:%s')

I get the error:

ValueError: time data '11/03/2004 00.00.00' does not match format '%d/%m/%y %H.%M.%S'

How can I solve it? The format seems correct to me

Answer 1

You're using the wrong year format, according to the documentation you should be using %Y instead of %y . %y is for years without the century.

Answer 2

from datetime import datetime
datetime.strptime('11/03/2004 00.00.00', '%d/%m/%Y %H.%M.%S')

Refer strftime() and strptime() Format Codes