如果 List 中的元素包含一个单词 | Python

Question

Say I have a list:

my_list = ["A", "B", "haha_test_haha", "C"]

I want to remove any and all elements that hold the substring test .

Output:

my_list = ["A", "B", "C"]

I've been trying list comprehensions with no luck. This would be the desired solution.

Note: I need only test to be removed. Not a list of words to remove.

---

My attempt:

my_list = ['A', 'B', 'C', 'C', 'ahahtestaagaga']

my_list = [remove for e in my_list if e.substring('test')]

print([sa for sa in a if not any(sb in sa for sb in b)])

Answer 1

my_list = [word for word in my_list if 'test' not in word]

Answer 2

Think about what it would look like as a for loop, so for the sake of the example, let's build a new list (even though it's inefficient), you want to capture things that don't have "test" as a substring:

new_list = []
for x in my_list:
    if "test" not in x:
        new_list.append(x)

So what would that look like as a comprehension?

my_list = [x for x in my_list if "test" not in x]