如何按字母顺序对 javascript 数组进行排序，最后是数字（字母之后），并正确地按数字排序？

Question

The current output of my array is:

"10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"

What I want is:

"AGUA", "BEAST", "KEN 5", "NEMCO", "9 VOLT", "10 FOOT", "45 RPM:, "910D0"

How do I achieve this?

Answer 1

You could check if the string starts with a digit and sort the rest by groups.

 const array = ['10 FOOT', '45 RPM', '9 VOLT', '910D0', 'AGUA', 'BEAST', 'KEN 5', 'NEMCO']; array.sort((a, b) => isFinite(a[0]) - isFinite(b[0]) || a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' }) ); console.log(array);

Answer 2

 const order = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"]; order.sort((a, b) => /^[0-9]/.test(a) - /^[0-9]/.test(b) || a.localeCompare(b, undefined, { numeric: true })); console.log(order);

Sort elements starting with a number first, afterwards use localeCompare's numeric option (which ensures "10" > "2").

Answer 3

 const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"]; const customCompare = (a, b) => /^\d/.test(a) - /^\d/.test(b) || a.localeCompare(b, undefined, { numeric: true }); const sorted = arr.sort(customCompare); console.log(...sorted);

Answer 4

You could create 2 new arrays, sort them and put them back together:

const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"];
const nums = arr.filter(a => parseInt(a))
const words = arr.filter(a => !parseInt(a))

nums.sort((a,b) => parseInt(a) -parseInt(b))
words.sort()

const finalArray = words.concat(nums)