如何按字母順序對 javascript 數組進行排序，最后是數字（字母之后），並正確地按數字排序？

Question

我陣列的當前 output 是：

"10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"

我想要的是：

"AGUA", "BEAST", "KEN 5", "NEMCO", "9 VOLT", "10 FOOT", "45 RPM:, "910D0"

我如何實現這一目標？

Answer 1

您可以檢查字符串是否以數字開頭並按組對 rest 進行排序。

 const array = ['10 FOOT', '45 RPM', '9 VOLT', '910D0', 'AGUA', 'BEAST', 'KEN 5', 'NEMCO']; array.sort((a, b) => isFinite(a[0]) - isFinite(b[0]) || a.localeCompare(b, undefined, { numeric: true, sensitivity: 'base' }) ); console.log(array);

Answer 2

 const order = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"]; order.sort((a, b) => /^[0-9]/.test(a) - /^[0-9]/.test(b) || a.localeCompare(b, undefined, { numeric: true })); console.log(order);

首先對以數字開頭的元素進行排序，然后使用 localeCompare 的數字選項（確保“10”>“2”）。

Answer 3

 const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"]; const customCompare = (a, b) => /^\d/.test(a) - /^\d/.test(b) || a.localeCompare(b, undefined, { numeric: true }); const sorted = arr.sort(customCompare); console.log(...sorted);

Answer 4

您可以創建 2 個新的 arrays，對它們進行排序並將它們重新組合在一起：

const arr = ["10 FOOT", "45 RPM", "9 VOLT", "910D0", "AGUA", "BEAST", "KEN 5", "NEMCO"];
const nums = arr.filter(a => parseInt(a))
const words = arr.filter(a => !parseInt(a))

nums.sort((a,b) => parseInt(a) -parseInt(b))
words.sort()

const finalArray = words.concat(nums)