[英]Applying function to a variadic template
I have a class that holds a map of Collection<T>
, which is cast into a void*
for storage purposes.我有一个 class ,它包含一个 map 的
Collection<T>
,它被转换成一个void*
用于存储目的。
Each Collection<T>
can hold an array of IDs, and I want to provide some variadic template magic to be able to tell if some ID exists in some grouping of Collection<T>
.每个
Collection<T>
可以保存一个 ID 数组,我想提供一些可变参数模板魔术来判断某个 ID 是否存在于Collection<T>
的某个分组中。 I'm just not sure how to go about it, after looking over some examples there is something that I am missing.我只是不确定如何 go 关于它,在查看了一些示例之后,我缺少一些东西。
template<typename T>
class A {
public:
void add_id(int id) {
ids.emplace_back(id);
}
bool has(int id) {
return std::find(ids.begin(), ids.end(), id) != ids.end();
}
private:
std::vector<int> ids {};
};
class Collection {
public:
template<typename T>
void insert(T* item) {
items.insert({std::type_index(typeid(T)), reinterpret_cast<void*>(item)});
}
template<typename T>
bool contains(int id) {
return reinterpret_cast<T*>(items[std::type_index(typeid(T))])->has(id);
}
template<typename T>
bool does_have(int id) {
return contains<T>(id);
}
template<typename First, typename... Rest>
bool does_have(int id) {
return contains<First>(id) && does_have<Rest...>(id);
}
template<typename First, typename Second, typename... Rest>
bool does_have(int id) {
return contains<First>(id) && does_have<Second, Rest...>(id);
}
private:
std::map<std::type_index, void*> items;
};
The idea is that, after storing some items in the Collection
class, I can do something like这个想法是,在
Collection
class 中存储一些项目后,我可以做类似的事情
collection.does_have<A<int>, A<bool>, A<double>, A<float>>(15)
And if the ID 15 exists in all 4, then does_have
returns true.如果 ID 15 存在于所有 4 个中,则
does_have
返回 true。 Otherwise, it's false.否则就是假的。
if you have c++17
(fold expression)如果你有
c++17
(折叠表达式)
template<typename ...Ts>
bool does_have(int id) {
return (contains<Ts>(id) && ...);
}
You can get your code to work providing only two overloads of does_have
:你可以让你的代码工作只提供两个重载的
does_have
:
template<typename T>
bool does_have(int id) {
and和
template<typename First, typename... Rest>
bool does_have(int id) {
but the latter should be visible only if the size of parameters pack Rest
is greater than 0. You can do this by SFINAE:但后者只有在参数包
Rest
的大小大于 0 时才可见。您可以通过 SFINAE 执行此操作:
template<typename First, typename... Rest,
std::enable_if_t<(sizeof...(Rest) > 0)>* = nullptr> // <---
bool does_have(int id) {
return contains<First>(id) && does_have<Rest...>(id);
}
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