Python：将 lambda 应用于行中列表的每个元素

Question

How can I apply lambda to echa element of list in a row?

I have a column with list of 2 elements in each row.

Those elelemts are strings and I want to make them ints.

Now: ['111', '222'] Then: [111, 222]

How to pass iteration thru each element of a list in a row?

df.column.apply(lambda x: int(x) for x in...

And I'm stuck here not knowing how to iterate since I already told lambda to work with x where x is a certain cell.

Thank you in advance.

Data Sample screenshot enclosed. enter image description here The problem is with 'coords' column.

Answer 1

Have you tried indexing into the list?

df.column.apply(lambda x: [int(x[0]), int(x[1])] for x in...

EDIT:

As your column sometimes contains None, try this:

df.column.apply(lambda x: x if pd.isnull(x) else [int(x[0]), int(x[1])]

This assumes that the problem values are None and not something like ['111', None]

Answer 2

SOLVED: I don't know why but this worked:

df.column.apply(lambda x: (float(x[0]), float(x[1])) if pd.isna([x]).any() == False else x)