行 *x=y 是否等于 c 中的行 x[0]=y

Question

in c, when allocating a new dynamic memory with malloc:在 c 中，当使用 malloc 分配新的动态 memory 时：

int* x = (int*)malloc(sizeof(x));
int y = 10;

is this line:这条线是：

*x = y;

equal to this line:等于这一行：

x[0] = y;

Answer 1

The definition of the [] operator is: given ex1[ex2] , it is guaranteed to be equivalent to []运算符的定义是：给定ex1[ex2] ，保证等价于

*((ex1) + (ex2))

Where ex1 and ex2 are expressions.其中ex1和ex2是表达式。

In your case x[0] == *(x + 0) == *(x) == *x .在您的情况下x[0] == *(x + 0) == *(x) == *x 。