is the line *x=y equal to the line x[0]=y in c

Question

in c, when allocating a new dynamic memory with malloc:

int* x = (int*)malloc(sizeof(x));
int y = 10;

is this line:

*x = y;

equal to this line:

x[0] = y;

Answer 1

The definition of the [] operator is: given ex1[ex2] , it is guaranteed to be equivalent to

*((ex1) + (ex2))

Where ex1 and ex2 are expressions.

In your case x[0] == *(x + 0) == *(x) == *x .

See Do pointers support "array style indexing"? for details.