[英]Regex: remove everything except the letters and separator
I am currently using replace statements to replace certain parts of a string.我目前正在使用替换语句来替换字符串的某些部分。 I think my code is a bit over the top and could be simplified:
我认为我的代码有点过头了,可以简化:
const locales = 'fr-CH, fr;q=0.9, en;q=0.8, de;q=0.7, *;q=0.5'
locales = locales.replace('-','_')
locales = locales.replace(';q=','')
locales = locales.replace(/[0-9]/g,'')
locales = locales.replace('.','')
In the end, I want to remove everything except for the locale from the string using regex and replace -
with _
.最后,我想使用正则表达式从字符串中删除除语言环境之外的所有内容,并将
-
替换为_
。 I would like the final string to look like this:我希望最终的字符串看起来像这样:
'fr_CH, fr, en, de, *'
You could replace and search for two small characters and possible following dash and some more upper case characters or a star.您可以替换和搜索两个小字符,并可能在破折号和一些大写字符或星号之后。
const locales = 'fr-CH, fr;q=0.9, en;q=0.8, de;q=0.7, *;q=0.5', parts = locales.replace(/-/g, '_').match(/[az]{2}_*[AZ]*|\*/g).join(', '); console.log(parts);
An even shorter approach which relaces all parts after semicolon (inclusive) until following comma without converting/matching to an array an joining back to a string.一种更短的方法,它替换分号(包括)之后的所有部分,直到逗号之后,而不转换/匹配到数组并连接回字符串。
const locales = 'fr-CH, fr;q=0.9, en;q=0.8, de;q=0.7, *;q=0.5', parts = locales.replace(/-/g, '_').replace(/;[^,]+/g, '') console.log(parts);
A carefully chosen regular expression can strip out the weightings in one replacement.精心挑选的正则表达式可以在一次替换中去掉权重。 A second switches the hyphens
-
for underscores _
第二个切换连字符
-
用于下划线_
const locales = 'fr-CH, fr;q=0.9, en;q=0.8, de;q=0.7, *;q=0.5';
newLocales = locales.replace(/;q=\d*\.\d*/g,'').replace(/-/g,'_');
console.log(newLocales); // fr_CH, fr, en, de, *
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