[英]In SQL, I need to the max of a column and return the max and the corresponding date
I have been researching this problem and have found a couple of similar questions, but none of the answers provided have worked for my situation.我一直在研究这个问题并发现了几个类似的问题,但所提供的答案都不适用于我的情况。 So, I wanted to reach out and directly pose my aituation
所以,我想伸出手直接摆出我的姿势
Basically, I need to return a max value where months are equal to January, February, or march (first quarter) and so on with the second quarter through the fourth quarter for each name and return the correspinding date that max value occurred.基本上,我需要返回一个最大值,其中月份等于 1 月、2 月或 3 月(第一季度)等等,每个名称的第二季度到第四季度,并返回最大值发生的对应日期。
For example, my table maybe looks like this: (However, there are many more names and date and money values)例如,我的表可能看起来像这样:(但是,还有更多的名称、日期和货币值)
Name![]() |
Money![]() |
Date![]() |
---|---|---|
John![]() |
1000 ![]() |
1-15-20 ![]() |
John![]() |
200 ![]() |
5-30-20 ![]() |
John![]() |
2000 ![]() |
8-30-20 ![]() |
John![]() |
800 ![]() |
11-19-20 ![]() |
And i would need a table return like this:我需要一个这样的表返回:
Name![]() |
Q1 Max ![]() |
Date![]() |
Q2 Max ![]() |
Date![]() |
Q3 Max ![]() |
Date![]() |
Q4 Max![]() |
Date![]() |
---|---|---|---|---|---|---|---|---|
John![]() |
1000 ![]() |
1-15-20 ![]() |
200 ![]() |
5-30-20 ![]() |
2000 ![]() |
8-30-20 ![]() |
800 ![]() |
11-19-20 ![]() |
The query you are looking for should look like this:您要查找的查询应如下所示:
with data as (
select 'John' as name, 1000 as "money", cast('1-15-20' as date) as "date" union all
select 'John', 200, cast('5-30-20' as date) union all
select 'John', 2000, cast('8-30-20' as date) union all
select 'John', 800, cast('11-19-20' as date)
)
select
name,
max(case when month("date") in (1,2,3) then money else null end) as Q1Max,
max(case when month("date") in (1,2,3) then date else null end) as "DateQ1",
max(case when month("date") in (4,5,6) then money else null end) as Q2Max,
max(case when month("date") in (4,5,6) then date else null end) as "DateQ2",
max(case when month("date") in (7,8,9) then money else null end) as Q3Max,
max(case when month("date") in (7,8,9) then date else null end) as "DateQ3",
max(case when month("date") in (10,11,12) then money else null end) as Q4Max,
max(case when month("date") in (10,11,12) then date else null end) as "DateQ4"
from data
group by name
You just need to get the max when the months are in the group of the condition in the case when
您只需要在月份处于条件组的
case when
获得最大值
OUTPUT OUTPUT
name![]() |
Q1Max ![]() |
DateQ1![]() |
Q2Max ![]() |
DateQ2![]() |
Q3Max ![]() |
DateQ3![]() |
Q4Max ![]() |
DateQ4![]() |
---|---|---|---|---|---|---|---|---|
John![]() |
1000 ![]() |
2020-01-15 ![]() |
200 ![]() |
2020-05-30 ![]() |
2000 ![]() |
2020-08-30 ![]() |
800 ![]() |
2020-11-19 ![]() |
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