C 包含要放入字符串数组的子字符串的字符数组

Question

Given char *line = {'a','\0','b','\0', 'c', '\0'}

how would you make it so that char **str_arr would point/be assigned to all the substrings within line ?

str_arr[str_arr_index] = line works only for the first substring, but anything after it is just NULL

Answer 1

str_arr = malloc(3 * sizeof (char *));
str_arr[0] = &line[0];
str_arr[1] = &line[2];
str_arr[2] = &line[4];

There is no way to do it programmatically because there is no way to know how many substrings line contains. (Just as there is no way from the output of the code above to know that str_arr now has three pointers to three substrings.)

Answer 2

First of all the statement

char *line = {'a','\0','b','\0', 'c', '\0'}

is not valid this can only be an array like the following

char *line = {'a','\0','b','\0', 'c', '\0'}

Here is a code sample that generates substrings

#include "stdlib.h"
#include "stdio.h"

int main()
{   
    char line[] = {'a','\0','b','\0', 'c', 'v', '\0', 'd', 'e', '\0'};
    
    int size = sizeof(line) / sizeof(char);
    int count = 0;
    int start = 0;
    
    char *str_arr[size];   // the size can be optimized with reallocs or by counting the terminatin chars in the line
    
    for (int i = 0; i < size; ++i) {
        if (line[i] == '\0') {
            str_arr[count] = &line[start];
            printf("string #%d -> %s \n", count + 1, str_arr[count]);
            start = i + 1;
            ++count;
        }
    }   
    
    return 0;
}